MZL's Border  Problem's Link:  http://acm.hdu.edu.cn/showproblem.php?pid=5351   Mean:  给出一个类似斐波那契数列的字符串序列,要你求给出的f[n]字符串中截取前m位的字符串s中s[1...i] = s[s.size()-i+1....s.size()]的最大长度。 analyse:   过计算

传送门：【HDU】5343 MZL’s Circle Zhou 对于a串可能和b串重复的部分，我们总能找到一个位置，使得a串达到最长，即a串的后继为空，所以我们只要预处理以字符x为开头的b串的个数即可。 my  code: my~~code: #include <bits/stdc++.h>using namespace std ;typedef long long LL ;#defin

Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to know the xor of all (Ai+Aj)(1≤i,j≤n) The xor of an array B is defined as B1 xor B2...xor Bn   Input

Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to know the xor of all (Ai+Aj)(1≤i,j≤n)The xor of an array B is defined as B1 xor B2...xor Bn