majority专题

Leetcode18: Majority Element

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element al

Leetcode180: Majority Element II

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 因为不超过n/3个数的数最多只有2个，可以定义两个变量，利用类似Majority Element中

leetcode oj java 169. Majority Element

一、问题描述： Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority

[LeetCode] 169. Majority Element

题目内容 https://leetcode-cn.com/problems/majority-element/ Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋times. You may assume

leetcode 229:Majority Element II

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. 题目分析：这道题跟Majority Element类似，我想到摩尔投票。摩尔投票的原理：

这道题目要求数组中最多的那个元素，这道题目的解法比较直观，直接遍历元素也可以有一个很好的时间复杂度。注意这里的遍历要求技巧，我们可以建立一个哨兵元素，并且记录哨兵元素出现的次数，如果遍历到的元素和哨兵元素一样那么次数加1，如果不一样则次数减1，直到次数不大于0的时候说明该哨兵元素暂时不是数组中次数最多的，此时更换哨兵元素为当前遍历到的元素，然后重复即可。注意这里定义次数最多的元素是大于[n/2]的

LeetCode 229 Majority Element II (投票算法)

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. Example 1: Input: nums = [3,2,3]Output: [3] Example 2: Input: nums = [1]Output: [1] Example 3: Input:

【leetcode】169. Majority Element 求众数

要求求出给定数组中出现频率大于 n / 2的数，那么这个数显然只可能有1个。题目为： Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the ar

USACO 2024年1月铜组 MAJORITY OPINION（思维模拟）

第一题：MAJORITY OPINION 标签：思维、模拟题意：给定一个长度为 n n n的序列 a a a，操作：若区间 [ i , j ] [i,j] [i,j]内某个数字 k k k出现的次数大于区间长度的一半，可以将区间内的所有数都换成这个数 k k k。经过多次操作之后，让区间 [ 1 , n ] [1,n] [1,n]内都为同一个数，输出所有可能的数（按照数字递增的顺序），若没

USACO 2024年1月铜组 MAJORITY OPINION

第一题：MAJORITY OPINION 标签：思维、模拟题意：给定一个长度为 n n n的序列 a a a，操作：若区间 [ i , j ] [i,j] [i,j]内某个数字 k k k出现的次数大于区间长度的一半，可以将区间内的所有数都换成这个数 k k k。经过多次操作之后，让区间 [ 1 , n ] [1,n] [1,n]内都为同一个数，输出所有可能的数（按照数字递增的顺序），若没

leetcode169~Majority Element

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element alwa

LeetCode： Majority Element

题目： Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element

229. Majority Element II 【M】【52】

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it poss

229.Majority Element II

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Hint: How many majority elements could it pos

169. Majority Element(Leetcode每日一题-2020.03.13)

Problem Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority ele

Leetcode#169. Majority Element

题目描述：一个非空数组，里面有元素出现了数组长度一半以上，返回这个元素解题思路：最容易想的是排序，返回中间那个元素即可，时间复杂度O(nlog(n))，空间复杂度O(l)；另一种思路借助于哈希表，遍历数组每一个元素，出现次数记录在hash表中，若hash值超过了数组长度的一半，返回这个元素即可，时间复杂度O(n)，空间复杂度O(n)。 C++实现如下：解法一：排序 class Sol

求一个数组的众数----------Majority Element169

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element alwa

169. Majority Element(关于摩尔投票法)

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element alwa

LeetCode之Majority Element II

/*O(n)解法。此题与Majority Element类似，考查摩尔投票的知识迁移。由于每个Majority Element的都more than⌊ n/3 ⌋，那么一个数组中顶多有两个Majority Elements。因此，可以先确定这个两个可能的元素，由于可能存在0个，1个，2个Majority Element，所以需要在确定这两个元素后进行检查。参考自：http://www.cn

169. 多数元素(majority-element)

169. 多数元素(majority-element) 给定一个大小为 n 的数组 nums ，返回其中的多数元素。多数元素是指在数组中出现次数大于 ⌊ n/2 ⌋ 的元素。你可以假设数组是非空的，并且给定的数组总是存在多数元素。示例 1：输入：nums = [3,2,3]输出：3 示例 2：输入：nums = [2,2,1,1,1,2,2]输出：2 提示： n

169. Majority Element--寻找数组中出现次数超过一半的数据，229. Majority Element II--注意最后的检测

第一题、169. Majority Element- Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty a

数据结构与算法笔记: 减治策略之Heap,Binary Search,Selection Sort, Heap Sort,Insertion Sort,Quick Select,Majority

Heap 堆的补充从逻辑结构上理解堆是一种树形结构，这种树是一种几乎完美的树，也就是完全二叉树完全二叉树 complete binary tree特点是：在非(倒数第一和倒数第二)层结构上的节点都是孩子双全的在倒数第一和倒数第二层结构上的节点是没有分支或单分支的在倒数第二层：叶子节点必须紧密排列在右侧在倒数第一层：叶子节点必须紧密排列在左侧宏观上看就像是一棵三角形的树，在右下侧可能会有

[LeetCode 229] Majority element II

Given an integer array of size n, find all elements that appear more than ⌊ n/3 ⌋ times. The algorithm should run in linear time and in O(1) space. Solution: At most has two elements in the resu

[LeetCode 153] Majority Element

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element al

LeetCode 面试题 17.10. Find Majority Element LCCI【摩尔投票法】简单

本文属于「征服LeetCode」系列文章之一，这一系列正式开始于2021/08/12。由于LeetCode上部分题目有锁，本系列将至少持续到刷完所有无锁题之日为止；由于LeetCode还在不断地创建新题，本系列的终止日期可能是永远。在这一系列刷题文章中，我不仅会讲解多种解题思路及其优化，还会用多种编程语言实现题解，涉及到通用解法时更将归纳总结出相应的算法模板。为了方便在PC上运行调试、分享代