package string; public class 幸运数 { public static void main(String[] args) { //int count=0; //for( int i=1;i<11;i++) xys(4); //System.out.println(xys(i)); } public
Good Luck in CET-4 Everybody! Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5488 Accepted Submission(s): 3530 Problem Description
There is a long time I haven't write something about my English learning .Yesterday I read a book writen by 艾力 and one of his words in the book impreesd me . He said:"If you want to learn Engli
巴什博弈: 一堆物品n个,最多取m个,最少取1个,最后取走的人获胜 分析:只要保证取玩最后剩m+1个,则必定胜利,所以构造m+1,只要n是 m+1的倍数,则先手必败,每次先手取玩,后手可取使得剩下的仍然是m+1的倍数,直到最后,剩下m+1个 Good Luck in CET-4 Everybody! Time Limit: 1000/1000 MS (Java/Others) Memo