justification专题

LeetCode 68 Text Justification

题意: 给出许多单词和一行能显示的最大长度,将所有单词按照两端对齐的方式进行排版,最后一行左对齐并用空格补齐长度。 思路: 一行一行的排版,每一行检查最多能放几个单词,即先假设单词之间只用1个空格分隔。 确定了一行要显示的单词数后,判断是否为最后一行,如果是,那么单词间用1个空格分隔,最后补空格到行最大长度;若不是最后一行,则每个单词后跟几个空格需要计算,计算方法见代码19和20行。

68. Text Justification

https://leetcode.com/problems/text-justification/description/ 给定一个单词数组和一个长度 maxWidth,重新排版单词,使其成为每行恰好有 maxWidth 个字符,且左右两端对齐的文本。 你应该使用“贪心算法”来放置给定的单词;也就是说,尽可能多地往每行中放置单词。必要时可用空格 ’ ’ 填充,使得每行恰好有 maxWidth

Text Justification

题目: Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach;

leetcode-68. Text Justification

leetcode-68. Text Justification 题目: Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack you

leetcode解题方案--068--Text Justification

题目 Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified. You should pack your words in a greedy approach; that

[leetcode刷题系列]Text Justification

- - 模拟题, 不过写的时候要仔细, 而且要理解好题意, 其实不难。 不过我写的时候因为没理解好题意,一开始写错了- -, 每行的单词之间至少要有一个空格的。这点特别注意, 其他就没啥了 class Solution {string getString(vector<string> &words, int st, int en, int L){// specialif(st ==