inorder专题

PreOrder, InOrder, PostOrder 题型总结

最基本的 Preorder, Inorder, Postorder Traverse Binary Tree Preorder traverse (用stack模拟，先进去right ，再进去left） Binary Tree Inorder traverse （用stack模拟，每次push整个左枝的所有node，再变换到右边); Binary Tree Postorder travers

LeetCode | Binary Tree Inorder Traversal

Given a binary tree, return the inorder traversal of its nodes’ values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you

105. Construct Binary Tree from Preorder and Inorder Traversal 递归构建树

已知树的先序和中序遍历结果，构建原树先序可以确定根节点，在中序遍历中找到与根节点对应的数值的索引，其左侧为左子树，右侧为右子树。递归构建；需要几个参数，先序遍历的起始索引（只确定根节点），中序遍历的起始索引，中序遍历的截止索引（起始到终止索引为子树的范围） public class Solution {public TreeNode buildTree(int[]

【LeetCode】Construct Binary Tree from Preorder and Inorder Traversal 根据先序序列和中序序列恢复二叉树

题目：Construct Binary Tree from Preorder and Inorder Traversal <span style="font-size:18px;">/**LeetCode * 题意：给定一个二叉树的先序遍历和中序遍历的序列，重建二叉树* 思路：先序遍历的第一个节点是父节点，中序遍历从第一个节点到父节点的都是父节点的左子树，父节点后面的都是父节点的右子树*

Construct Binary Tree from Preorder and Inorder Traversal问题及解法

问题描述： Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 问题分析：已知树的先序和中序遍历的结果，我们可以依此来分别构建左子树、右子树和树根，递归求解即可

Binary Tree Inorder Traversal问题及解法

问题描述： Given a binary tree, return the inorder traversal of its nodes' values. 示例： Given binary tree [1,null,2,3], 1\2/3 return [1,3,2]. 问题分析：利用二叉树的先序遍历，先遍历左子树，后父节点，最后遍历右子树。过程详见

leetcode No106. Construct Binary Tree from Inorder and Postorder Traversal

Question： Given inorder and postorder traversal of a tree, construct the binary tree. 根据树的中序遍历和后序遍历构建二叉树 Algorithm：中序遍历：左-根-右后序遍历：左-右-根举个例子中序遍历：DBEAFCG 后序遍历：DEBFGCA 1、后序遍历的最后一

leetcode No105. Construct Binary Tree from Preorder and Inorder Traversal

Question: Given preorder and inorder traversal of a tree, construct the binary tree. 根据树的前序遍历和中序遍历，构建二叉树 Algorithm：前序遍历：根-左-右中序遍历：左-根-右举个例子前序遍历：ABDECFG 中序遍历：DBEAFCG

leetcode No94. Binary Tree Inorder Traversal

Question: Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1\2/3 return [1,3,2]. Note: Recursive solution is trivi

Leetcode 106 Construct Binary Tree from Inorder and Postorder Traversal（二叉树）

题目连接：Leetcode 106 Construct Binary Tree from Inorder and Postorder Traversal 解题思路：参考 Leetcode 105。 /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;*

Leetcode 105 Construct Binary Tree from Preorder and Inorder Traversal（二叉树）

题目连接：Leetcode 105 Construct Binary Tree from Preorder and Inorder Traversal 解题思路：p指针在二叉树的中序遍历上移动，inorder[p]即为当前结点的值，然后找到preorder中找到inorder[p]的位置t，根据前序遍历的性质，在preorder中，start~t-1的结点应该是当前结点的左子树，t+1~end的

LeetCode 题解（155）: Construct Binary Tree from Inorder and Postorder Traversal

题目： Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 题解：递归。 C++版： class Solution {public:TreeNode*

LeetCode 题解(266) : Inorder Successor in BST

题目： Given a binary search tree and a node in it, find the in-order successor of that node in the BST. Note: If the given node has no in-order successor in the tree, return null. 题解：用了递归。循环应该略有难

LeetCode - construct-binary-tree-from-preorder-and-inorder-traversal

题目: Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 题意：根据前序序列和中序序列来构造二叉树可以假设二叉树中没有重复的数解题思路：中

LeetCode - construct-binary-tree-from-inorder-and-postorder-traversal

题目： Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 题意：给你一个二叉树的中序序列和后序序列，确定二叉树。里面的结点不重复解题思路：

leetcode:(94) Binary Tree Inorder Traversal(java)

package HashTable;/*** 题目：* Given a binary tree, return the inorder traversal of its nodes' values.* 解题思路：* 从根节点开始，先将根节点压入栈，然后再将其所有左子结点压入栈，然后取出栈顶节点，保存节点值，* 再将当前指针移到其右子节点上，若存在右子节点，则在下次循环

[LeetCode]94.Binary Tree Inorder Traversal

【题目】 Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1\2/3 return [1,3,2]. Note: Recursive solution is trivial, cou

LeetCode 106：Construct Binary Tree from Postorder and Inorder Traversal

Given inorder and postorder traversal of a tree, construct the binary tree. 给定一个二叉树的后序和中序遍历，重建这棵二叉树。此题和LeetCode105 根据前序和中序重建二叉树类似。所谓后序遍历，即先访问根的左、右子树，然后再访问根节点。这样根节点在二叉树后序遍历的最后一个个元素。所谓中序遍历

LeetCode 94：Binary Tree Inorder Traversal（中序遍历）

Given a binary tree, return the inorder traversal of its nodes’ values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. 题目要求对二叉树进行非递归的中序遍历，所谓中序遍历即，先访问左子树、再访问根节点、然后是右子树。通常采

#94 Binary Tree Inorder Traversal——Top 100 Liked Questions

Given a binary tree, return the inorder traversal of its nodes' values. Example: Input: [1,null,2,3]1\2/3Output: [1,3,2] Follow up: Recursive solution is trivial, could you do it iteratively? 第一次

leetcode 094 Binary Tree Inorder Traversal

Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1\2/3 return [1,3,2]. Note: Recursive solution is trivial, could you

leetcode106~Construct Binary Tree from Inorder and Postorder Traversal

Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据中序遍历和后序遍历创建一棵二叉树。思路与上题类似。关键在于，上下限的选取。下面两种方法，不同在于上下限选

leetcode105~Construct Binary Tree from Preorder and Inorder Traversal

Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 根据前序遍历和中序遍历可以唯一的确定一棵二叉树代码如下，使用递归 public static TreeNode

106. Construct Binary Tree from Inorder and Postorder Traversal【M】【31】

Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. Subscribe to see which companies asked this

Inorder Successor in Binary Search Tree

Given a binary search tree (See Definition) and a node in it, find the in-order successor of that node in the BST. If the given node has no in-order successor in the tree, return null. 使用中序遍历的方式进

leetcodeBinary Tree Inorder Traversal

题目描述 Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1\2/3 return [1,3,2]. Note: Recursive solution is trivial, could you