buy专题
【POJ】Buy Tickets（思路 + 线段树）
一开始没有思路，之后问了一下学长，需要逆向处理输入。 最后一个加入队列的肯定是没有冲突的，所以我们可以从最后一个开始处理，从后往前，找第 i + 1个空着的地方。 线段树的话记录 区间中 空白位置的个数。 134418332013010521002828Accepted5368K1704MSC++1690B2014-09-14 21:19:45 #include<iost
Leetcode:72 Best Time to Buy and Sell Stock
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock),
POJ 2828 Buy Tickets (线段树，单点更新)
http://poj.org/problem?id=2828 Buy Tickets Time Limit: 4000MS Memory Limit: 65536KTotal Submissions: 12307 Accepted: 6080 Description Railway tickets were difficult to buy around the Lunar Ne
Buy Tickets ---- 线段树单点更新
Buy Tickets Time Limit: 4000MS Memory Limit: 65536KTotal Submissions: 13819 Accepted: 6906 Description Railway t
leetcode122-Best Time to Buy and Sell Stock II
题目 给你一个整数数组 prices ，其中 prices[i] 表示某支股票第 i 天的价格。 在每一天，你可以决定是否购买和/或出售股票。你在任何时候 最多 只能持有 一股 股票。你也可以先购买，然后在 同一天 出售。 返回 你能获得的 最大 利润 。 示例 1： 输入：prices = [7,1,5,3,6,4] 输出：7 解释：在第 2 天（股票价格 = 1）的时候买入，在第 3 天（股
**Leetcode 123 Best Time to Buy and Sell Stock III
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/description/ O(n^2)的做法就不解释了，枚举划分的位置即可。但是关键点在最多两次，所以可以考虑前缀后缀和。 先说O(n^2)的 class Solution {public:int maxProfitForOne(vector<int>&
Leetcode Best Time to Buy and Sell Stock
https://leetcode.com/problems/best-time-to-buy-and-sell-stock/description/ O(n^2)的就不用说了，一层遍历start_idx 一层遍历end_idx， 所以要在O(n)时间做的话 就是一次遍历记录两个位置，特殊点在于， start_idx总是当前最小， 答案一定的在这样的解中产生，就是 当前值减去当前最小值。
*** Leetcode 309. Best Time to Buy and Sell Stock with Cooldown | dp
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-with-cooldown/description/ 因为做过之前那个题，所以还是能比较快做出来的。 做法1： dp[i][0]: 第i天卖，完成i次买和卖 dp[i][1]:第i天买，完成i-1次卖和i次买 class Solution {public:int
《leetCode》：Best Time to Buy and Sell Stock III
题目 Say you have an array for which the ith element is the price of a given stock on day i.Design an algorithm to find the maximum profit. You may complete at most two transactions. 思路一：报超时错误 思路：分而治
《leetCode》：Best Time to Buy and Sell Stock II
题目 Say you have an array for which the ith element is the price of a given stock on day i.Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy o
LeetCode 121. Best Time to Buy and Sell Stock
121. Best Time to Buy and Sell Stock 一、问题描述 Say you have an array for which the i*th element is the price of a given stock on day *i. If you were only permitted to complete at most one transaction
51.Best Time to Buy and Sell Stock（动态规划）
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock),
50.Best Time to Buy and Sell Stock II(贪心算法)
题目原文： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (
POJ Buy Tickets
题目分析： 给你N个人的队列，每个人都有想站的位置，要你从前往后的给他们排序，输出最后的结果。注意，后面的人会覆盖前面的。就是是原本在该位置上的人往后移动一个位置。 算法分析： 我们可以把总人数当作区间的大小，然后结果就是把区间的每一个位置都放上人，就是答案了。 而从题目中我们可以知道，后面的人是不受前面的人的影响的。所以，我们可以倒这来模拟过程。 如何模拟呢？我们可以想到用
poj1952 BUY LOW, BUY LOWER
求不重复个数好难 #include<iostream>#include<cstring>#include<cstdio>using namespace std;int a[5005],f[5005],count[5005];int main(){int n;int i,j;while(scanf("%d",&n)!=EOF){for(i=0;i<n;i++){count[i]=1;f[
618大促有哪些值得买的家居好物？618五款必Buy好物
来了！来了！万众瞩目的618购物狂欢节即将拉开帷幕，我们的目标清晰而坚定，那就是用最实惠的价格尽情享受购物的乐趣。然而，面对各种纷繁复杂的促销活动和琳琅满目的商品，选择困难症似乎也在悄然滋生。因此，我今天特意为大家精选了一系列家居好物，它们不仅实用到让人惊叹，而且价格更是诚意满满，绝对比平时更加划算。希望这些好物能够成为你618购物之旅的得力助手，让你轻松享受购物的乐趣，不再为选择而烦恼！ 一、
LeetCode *** 121. Best Time to Buy and Sell Stock
题目： Say you have an array for which the ith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the sto
Think I’ll Buy Me a Football Team-2924
题目：http://acm.hdu.edu.cn/showproblem.php?pid=2924 代码： #include<iostream>using namespace std;int main(){int num=0,fsum=0,lsum=0,k=1;while(cin>>num&&num!=0){int **p=new int*[num];for(int i=0;i<num;
buy me a btc 使用数字货币进行打赏赞助
最近在调研使用加密货币打赏的平台，发现idatariver平台 https://idatariver.com 推出的buymeabtc功能刚好符合使用场景，下图为平台的演示项目, 演示项目入口 https://buymeabtc.com/idatariver 特点 不少人都听说过buymeacoffee，可以在上面发布数字商品或者赞助收款，但是相对门槛会比较高，而基于加密货币的buymea
【启发】leetcode - 121. Best Time to Buy and Sell Stock 【动态规划 + 连续区间问题 + 试探性购买】
题目 Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the sto
poj 2828 Buy Tickets(动态队列·线段树单点更新)
题目：http://poj.org/problem?id=2828 大意：一群人排队，第i个人来到队伍中站到处于posi的人的右边，且每个人都有不同的表示值，问最终的结果？ Sample Input 40 771 511 332 6940 205231 192431 38900 31492 Sample Output 77 33 69 5131492 20523 3
Leetcode 123 Best Time to Buy and Sell Stock III
原题： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may n
[leetcode] 122. Best Time to Buy and Sell Stock II
这是一个非常简单贪心问题，贪心问题的解决方法一般都非常简单，但是要想到这个方法真的挺不容易的： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may comple
图像检索：Where to Buy It: Matching Street Clothing Photos in Online Shops
intro: ICCV 2015 hmepage: http://www.tamaraberg.com/street2shop/ paper: http://www.tamaraberg.com/papers/street2shop.pdf paper: http://www.cv-foundation.org/openaccess/content_iccv_2015/html/Ki