本文主要是介绍ICode国际青少年编程竞赛- Python-1级训练场-综合训练1,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
ICode国际青少年编程竞赛- Python-1级训练场-综合训练1
1、
Spaceship.turnLeft()
for i in range(2):Spaceship.turnLeft()Spaceship.step(3)
Dev.step(-1)
Spaceship.step(4)
Spaceship.turnLeft()
Spaceship.step(3)
2、
Spaceship.step()
Spaceship.turnLeft()
Spaceship.step(3)
Dev.step(2)
Dev.turnRight()
Dev.step(2)
Dev.step(-4)
3、
for i in range(3):Spaceship.step(4)Spaceship.turnLeft()
4、
for i in range(6):Dev.turnLeft()Dev.step(2)Dev.turnRight()Dev.step(2)
5、
for i in range(4):Dev.step(1)Dev.turnRight()Dev.step(5)Dev.turnRight()Dev.step(1)Dev.turnLeft()
6、
for i in range(3):Dev.step(5)Dev.step(-3)Dev.turnLeft()Dev.step(3)Dev.turnRight()
7、
for i in range(3):Spaceship.step(2)Dev.step(2)Dev.step(-2)Spaceship.turnRight()Spaceship.step(2)Dev.step(-3)Dev.step(3)Spaceship.turnLeft()
8、
for i in range(3):Dev.step(4)Dev.turnLeft()
Dev.step(8)
for i in range(3):Dev.turnRight()Dev.step(4)
9、
Spaceship.turnLeft()
for i in range(3):Spaceship.step(3)Spaceship.turnRight()Spaceship.step(2)
10、
for i in range(4):Dev.step(2)Dev.step(-9)Dev.step(3)Dev.turnLeft()
11、
for i in range(3):Spaceship.step(3)Spaceship.turnLeft()Spaceship.step(4)Spaceship.turnRight()
12、
Dev.step(2)
for i in range(3):Dev.turnRight()Dev.step(4)
Dev.turnRight()
Dev.step(-2)
13、
Dev.turnLeft()
for i in range(3):Dev.step(3)Dev.step(-3)Spaceship.step(1)Spaceship.turnLeft()Spaceship.step(2)Spaceship.turnRight()Spaceship.step(1)
Dev.step(3)
14、
for i in range(3):Dev.step(i + 2)Dev.turnRight()Dev.step(i + 2)Dev.turnLeft()
15、
Dev.turnLeft()
for i in range(4):Dev.step(3)Dev.step(-3)Spaceship.step(4 - i)
16、
for i in range(4):Dev.step(2)Dev.turnRight()Dev.step(i + 1)Dev.turnLeft()
17、
for i in range(5):Spaceship.step(2)Spaceship.turnRight()Spaceship.step(i + 3)Spaceship.turnRight()Spaceship.turnRight()Spaceship.step(i + 3)Spaceship.turnRight()
18、
for i in range(4):Dev.turnLeft()Dev.step(i + 1)Dev.turnRight()Dev.step()
for i in range(3):Dev.step(5)Dev.turnRight()
19、
Dev.turnRight()
Spaceship.step()
for i in range(3):Spaceship.turnRight()Spaceship.step(i + 2)Dev.step(5 - i)Dev.step(-(5 - i))Spaceship.turnLeft()Spaceship.step(3 - i)
20、
for i in range(5):Spaceship.step(2)Spaceship.turnLeft()Spaceship.step(5 - i)Spaceship.turnLeft()Spaceship.turnLeft()Spaceship.step(7)Spaceship.turnLeft()Spaceship.turnLeft()Spaceship.step(2 + i)Spaceship.turnRight()
这篇关于ICode国际青少年编程竞赛- Python-1级训练场-综合训练1的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!