某音乐平台歌曲信息逆向之webpack扣取

本文主要是介绍某音乐平台歌曲信息逆向之webpack扣取，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

逆向网址

aHR0cHM6Ly95LnFxLmNvbS8=

逆向链接

aHR0cHM6Ly95LnFxLmNvbS9uL3J5cXEvc29uZ0RldGFpbC8wMDJkdzRndjFabWlHdA==

逆向接口

aHR0cHM6Ly91Ni55LnFxLmNvbS9jZ2ktYmluL211c2ljcy5mY2c=

逆向过程

请求方式：POST

逆向参数

sign zzbd8c72309rdslvlnjwk8pthj2lw462f12d2

过程分析

根据XHR断点方式可快速进入发包内容

向上找入口函数，折叠可知该函数【B】存在我们需要的参数

// queryString 参数1 _
if (e.url = C({_: Date.now()
}, e.url)// queryString 参数2 sign
e.url = C({sign: i
}, e.url)

那么定位到这里可知，只需要定位到参数【i】即可完成本次逆向

var i, o = n(147).default;
i = "GET" === e.type.toUpperCase() ? o(e.data.data) : o(e.data),

断点调试

断点可知：

【e.data】 POST请求参数

【o】方法则为 webpack导出后执行 ****************

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e < 32 * t.length; e += 8)n += String.fromCharCode(t[e >> 5] >>> e % 32 & 255);return n}(function(t, n) {t[n >> 5] |= 128 << n % 32,t[14 + (n + 64 >>> 9 << 4)] = n;var u, s, c, l, f, p = 1732584193, d = -271733879, h = -1732584194, v = 271733878;for (u = 0; u < t.length; u += 16)s = p,c = d,l = h,f = v,p = r(p, d, h, v, t[u], 7, -680876936),v = r(v, p, d, h, t[u + 1], 12, -389564586),h = r(h, v, p, d, t[u + 2], 17, 606105819),d = r(d, h, v, p, t[u + 3], 22, -1044525330),p = r(p, d, h, v, t[u + 4], 7, -176418897),v = r(v, p, d, h, t[u + 5], 12, 1200080426),h = r(h, v, p, d, t[u + 6], 17, -1473231341),d = r(d, h, v, p, t[u + 7], 22, -45705983),p = r(p, d, h, v, t[u + 8], 7, 1770035416),v = r(v, p, d, h, t[u + 9], 12, -1958414417),h = r(h, v, p, d, t[u + 10], 17, -42063),d = r(d, h, v, p, t[u + 11], 22, -1990404162),p = r(p, d, h, v, t[u + 12], 7, 1804603682),v = r(v, p, d, h, t[u + 13], 12, -40341101),h = r(h, v, p, d, t[u + 14], 17, -1502002290),p = i(p, d = r(d, h, v, p, t[u + 15], 22, 1236535329), h, v, t[u + 1], 5, -165796510),v = i(v, p, d, h, t[u + 6], 9, -1069501632),h = i(h, v, p, d, t[u + 11], 14, 643717713),d = i(d, h, v, p, t[u], 20, -373897302),p = i(p, d, h, v, t[u + 5], 5, -701558691),v = i(v, p, d, h, t[u + 10], 9, 38016083),h = i(h, v, p, d, t[u + 15], 14, -660478335),d = i(d, h, v, p, t[u + 4], 20, -405537848),p = i(p, d, h, v, t[u + 9], 5, 568446438),v = i(v, p, d, h, t[u + 14], 9, -1019803690),h = i(h, v, p, d, t[u + 3], 14, -187363961),d = i(d, h, v, p, t[u + 8], 20, 1163531501),p = i(p, d, h, v, t[u + 13], 5, -1444681467),v = i(v, p, d, h, t[u + 2], 9, -51403784),h = i(h, v, p, d, t[u + 7], 14, 1735328473),p = o(p, d = i(d, h, v, p, t[u + 12], 20, -1926607734), h, v, t[u + 5], 4, -378558),v = o(v, p, d, h, t[u + 8], 11, -2022574463),h = o(h, v, p, d, t[u + 11], 16, 1839030562),d = o(d, h, v, p, t[u + 14], 23, -35309556),p = o(p, d, h, v, t[u + 1], 4, -1530992060),v = o(v, p, d, h, t[u + 4], 11, 1272893353),h = o(h, v, p, d, t[u + 7], 16, -155497632),d = o(d, h, v, p, t[u + 10], 23, -1094730640),p = o(p, d, h, v, t[u + 13], 4, 681279174),v = o(v, p, d, h, t[u], 11, -358537222),h = o(h, v, p, d, t[u + 3], 16, -722521979),d = o(d, h, v, p, t[u + 6], 23, 76029189),p = o(p, d, h, v, t[u + 9], 4, -640364487),v = o(v, p, d, h, t[u + 12], 11, -421815835),h = o(h, v, p, d, t[u + 15], 16, 530742520),p = a(p, d = o(d, h, v, p, t[u + 2], 23, -995338651), h, v, t[u], 6, -198630844),v = a(v, p, d, h, t[u + 7], 10, 1126891415),h = a(h, v, p, d, t[u + 14], 15, -1416354905),d = a(d, h, v, p, t[u + 5], 21, -57434055),p = a(p, d, h, v, t[u + 12], 6, 1700485571),v = a(v, p, d, h, t[u + 3], 10, -1894986606),h = a(h, v, p, d, t[u + 10], 15, -1051523),d = a(d, h, v, p, t[u + 1], 21, -2054922799),p = a(p, d, h, v, t[u + 8], 6, 1873313359),v = a(v, p, d, h, t[u + 15], 10, -30611744),h = a(h, v, p, d, t[u + 6], 15, -1560198380),d = a(d, h, v, p, t[u + 13], 21, 1309151649),p = a(p, d, h, v, t[u + 4], 6, -145523070),v = a(v, p, d, h, t[u + 11], 10, -1120210379),h = a(h, v, p, d, t[u + 2], 15, 718787259),d = a(d, h, v, p, t[u + 9], 21, -343485551),p = e(p, s),d = e(d, c),h = e(h, l),v = e(v, f);return [p, d, h, v]}(function(t) {var e, n = [];for (n[(t.length >> 2) - 1] = void 0,e = 0; e < n.length; e += 1)n[e] = 0;for (e = 0; e < 8 * t.length; e += 8)n[e >> 5] |= (255 & t.charCodeAt(e / 8)) << e % 32;return n}(t), 8 * t.length))}function s(t) {return u(unescape(encodeURIComponent(t)))}return function(t) {var e, n, r = "";for (n = 0; n < t.length; n += 1)e = t.charCodeAt(n),r += "0123456789abcdef".charAt(e >>> 4 & 15) + "0123456789abcdef".charAt(15 & e);return r}(s(t))};var i = n._getSecuritySign;delete n._getSecuritySign,e.default = i}.call(this, n(110))
}

由调试可知方法： n(110) === window

, function(t, e) {var n;n = function() {return this}();try {n = n || new Function("return this")()} catch (r) {"object" === typeof window && (n = window)}t.exports = n
}

扣取代码

断点单步进入【o】内部

快速折叠方法后拉到文件最顶部可知该方式为 webpack 加载

(window.webpackJsonp = window.webpackJsonp || []).push([[0], [, function(t, e, n) {

那么回到调取执行方法部内，我们发现加载函数【n(110)】打上断点，或在上下函数中找方法【n】进行断点进入

加载器

标识

 return e[t].call(a.exports, a, a.exports, f),

代码

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}([]);

构建代码

整合代码

window = global;///
// location
location = {hash: "",host: {host},hostname: {hostname},href: {href},origin: {origin},pathname: "",port: "",protocol: "https:",search: ""
}
Location = function Location(){}
location.__proto__ = Location.prototype
window.location = location///
// navigator
navigator = {appCodeName: "Mozilla",appName: "Netscape",appVersion: "5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/121.0.0.0 Safari/537.36",language: "en",languages: [ "en", "zh-CN",  "zh",  "ja" ],platform: "Win32",product: "Gecko",productSub: "20030107",userAgent: "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/121.0.0.0 Safari/537.36",vendor: "Google Inc.",
}
Navigator = function Navigator(){}
Navigator.prototype.webdriver = false;
navigator.__proto__ = Navigator.prototypevar _util;
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