uva 10167 Birthday Cake

2024-03-24 08:48

文章标签 uva birthday 10167 cake

本文主要是介绍uva 10167 Birthday Cake，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

原题：
Lucy and Lily are twins.Today is their birthday.Mother buys a birthday cake for them. Now we put
the cake onto a Descartes coordinate. Its center is at (0,0), and the cake’s length of radius is 100.
There are 2N (N is a integer, 1 ≤ N ≤ 50) cherries on the cake. Mother wants to cut the cake into two halves with a knife (of course a beeline). The twins would like to be treated fairly, that means, the shape of the two halves must be the same (that means the beeline must go through the center of the cake) , and each half must have N cherrie(s). Can you help her?
Note: the coordinate of a cherry (x,y) are two integers. You must give the line as form two integers A,B (stands for Ax + By = 0) each number mustn’t in [−500,500]. Cherries are not allowed lying on the beeline. For each dataset there is at least one solution.
这里写图片描述
Input
The input file contains several scenarios. Each of them consists of 2 parts:
The first part consists of a line with a number N, the second part consists of 2N lines, each line
has two number, meaning (x,y). There is only one space between two border numbers. The input file
is ended with N = 0.
Output
For each scenario, print a line containing two numbers A and B. There should be a space between
them. If there are many solutions, you can only print one of them.
Sample Input
2
-20 20
-30 20
-10 -50
10 -5
0
Sample Output
0 1
大意：
给你一个直径是100的蛋糕，上面有2*n个草莓。现在让你找出A和B使得沿着直线AX+BY=0切割能使得两半的蛋糕上面有数目相同的草莓。（不会有两个草莓在一条直线上）

#include <bits/stdc++.h>using namespace std;
//fstream in,out;
struct point
{int x,y;
};
point p[101];
int main()
{ios::sync_with_stdio(false);int n;while(cin>>n,n){for(int i=1;i<=n*2;i++)cin>>p[i].x>>p[i].y;int flag=0,mark=0;int cnt=0,a,b;for(int A=-500;A<=500;++A){for(int B=-500;B<=500;++B){mark=cnt=0;int i;if(A==0&&B==0)continue;for(i=1;i<=n*2;i++){if(A*p[i].x+B*p[i].y==0){mark=1;break;}if(A*p[i].x+B*p[i].y<0)cnt++;}if(cnt==n&&mark==0){a=A;b=B;flag=1;break;}}if(flag)break;}cout<<a<<" "<<b<<endl;}return 0;
}