The Dragon of Loowater,UVa 11292

2024-02-22 15:48

文章标签 uva dragon loowater 11292

本文主要是介绍The Dragon of Loowater,UVa 11292，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

【题目】
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally,a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance. One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing
dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon
and save the kingdom.The knights explained: “To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon’s heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights’ union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight’s height.” Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the
king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!
【 Input】
The input contains several test cases. The first line of each test case contains two integers between 1 and
20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in
the kingdom. The next n lines each contain an integer, and give the diameters of the dragon’s heads,
in centimetres. The following m lines each contain an integer, and specify the heights of the knights of
Loowater, also in centimetres.
The last test case is followed by a line containing ‘0 0’.
【Output】
For each test case, output a line containing the minimum number of gold coins that the king needs to
pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the
line ‘Loowater is doomed!’.
【Sample Input】
2 3
5
4
7
8
4
2 1
5
5
10
0 0
【Sample Output】
11
Loowater is doomed!

【题解】
骑士的能力从小到大排序，头的大小从小到大排序，一个一个砍，不能砍掉”当前需要砍的头“的骑士就不要雇佣了。

#include <cstdio>
#include<algorithm>using namespace std;
const int maxn = 20000 + 5;
int A[maxn], B[maxn];int main() {int n, m;while (scanf("%d%d", &n, &m) == 2 && n && m) {for (int i = 0; i < n; i++) scanf("%d", &A[i]);for (int i = 0; i < m; i++) scanf("%d", &B[i]);sort(A, A + n);sort(B, B + m);int cur = 0;                  //当前需要砍掉的头的编号int cost = 0;                 //当前总费用for (int i = 0; i < m; i++)if (B[i] >= A[cur]) {cost += B[i];              // 雇佣该骑士cur++;if (cur == n) break;         //如果头已经砍完，及时退出循环}if (cur < n) printf("Loowater is doomed !\n");else printf("%d\n", cost);}return 0;
}