【leetcode C++】1642. 可以到达的最远建筑 1642. Furthest Building You Can Reach

1642. 可以到达的最远建筑
1642. Furthest Building You Can Reach

class Solution {
public:int furthestBuilding(vector<int>& heights, int bricks, int ladders) {priority_queue<int, vector<int>, greater<int> > PQ;  // 小顶堆，用来保存前ladders个最大值int sum = 0;  // 除了前ladders个最大值之外的和int cnt = 0;  //最远可以到达的下标for(int ii = 1; ii < heights.size(); ii++) {int height = max(0, heights[ii] - heights[ii - 1]);  // 高度差，取非负数PQ.push(height);if(PQ.size() > ladders) {sum += PQ.top();PQ.pop();if(sum > bricks) break;}cnt = ii;}return cnt;}
};