UVA-537 Artificial Intelligence?

本文主要是介绍UVA-537 Artificial Intelligence?，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

原题连接：

https://vjudge.net/problem/UVA-537

AC代码：

#include <bits/stdc++.h>
using namespace std;int main()
{int n;cin >> n;getchar();for (int t = 1; t <= n; t++){cout << "Problem #" << t << endl;char str[500];fgets(str, 500, stdin);double p = 0, u = 0, i = 0;int cnt = 0; //记录变量，两个就breakfor (int j = 0; str[j] != '\0'; j++){if (cnt == 2)break;if (str[j] == 'U' && str[j + 1] == '='){cnt++;char num[10];int z = 0;j = j + 2;while (str[j] != 'm' && str[j] != 'k' && str[j] != 'M' && str[j] != 'V'){num[z++] = str[j++];}num[z] = '\0';u = atof(num);if (str[j] == 'm')u *= 0.001;else if (str[j] == 'k')u *= 1000.0;else if (str[j] == 'M')u *= 1000000.0;continue;}if (str[j] == 'I' && str[j + 1] == '='){cnt++;char num[10];int z = 0;j = j + 2;while (str[j] != 'm' && str[j] != 'k' && str[j] != 'M' && str[j] != 'A'){num[z++] = str[j++];}num[z] = '\0';i = atof(num);if (str[j] == 'm')i *= 0.001;else if (str[j] == 'k')i *= 1000.0;else if (str[j] == 'M')i *= 1000000.0;continue;}if (str[j] == 'P' && str[j + 1] == '='){cnt++;char num[100];int z = 0;j = j + 2;while (str[j] != 'm' && str[j] != 'k' && str[j] != 'M' && str[j] != 'W'){num[z++] = str[j++];}num[z] = '\0';p = atof(num);if (str[j] == 'm')p *= 0.001;else if (str[j] == 'k')p *= 1000.0;else if (str[j] == 'M')p *= 1000000.0;continue;}}if (p == 0){printf("P=%.2lfW\n\n", u * i);}else if (u == 0){printf("U=%.2lfV\n\n", (p / i));}else if (i == 0){printf("I=%.2lfA\n\n", (p / u));}}return 0;
}