Leetcode 2047. Number of Valid Words in a Sentence [Python]

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展开了，把不符合条件的全部返回False。细心点就好了。

class Solution:def countValidWords(self, sentence: str) -> int:lst = sentence.split(' ')hyphens = Falseres = 0#print(lst)for part in lst:if part == '':continueif self.check(part):res += 1#print(part)#print(' ')return resdef check(self, part):N = len(part)countpunc = 0counthyphen = 0for i, letter in enumerate(part):if letter.isdigit():return Falseif letter.isalpha():continueif  N > 1 and i < N- 1 and (letter == '!' or letter == ',' or letter == '.'):return False#寻找合法的puncif letter == '!' or letter == ',' or letter == '.':countpunc += 1if countpunc > 1:return False#punc重复if letter == '-' and (i == 0 or i == N-1):return False#hyphen不在头尾if letter == '-' and (not part[i-1].isalpha() or not part[i+1].isalpha()):return False#hyphen前后不都是letterif letter == '-':counthyphen += 1if counthyphen > 1:return False#hyphen重复return True

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