Mlab中基于Numpy的3D绘图函数

2023-12-21 10:32

文章标签 函数 3d 绘图 numpy mlab

本文主要是介绍Mlab中基于Numpy的3D绘图函数，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

Python科学计算三维可视化
黄天羽、嵩天

Mlab 基础

mayavi.mlab.show(func = None, stop = False)

基于numpy绘图

mlab对Numpy建立可视化过程

建立数据源
使用Filter（可选）
添加可视化模块

3D绘图函数

`Points3d()`

基于Numpy数组x、 y、 z提供的三维点坐标，绘制点图形（0D数据）
函数形式：
points3d(x, y, z…)、points3d(x, y, z, s, …)、points3d(x, y, z, f, …)
x,y,z 表示 numpy 数组、列表或者其他形式的点三维坐标
s 表示在该坐标点处的标量值
f 表示通过函数f（x，y，z）返回的标量值
参数

from mayavi import mlab
import numpy as npt = np.linspace(0, 4*np.pi, 20)
x = np.sin(2*t)
y = np.cos(t)
z = np.cos(2*t)
s = 2 + np.sin(t)points = mlab.points3d(x, y, z, s, colormap = 'Reds', scale_factor = 0.25)
mlab.show()

points3d

`Plot3d()`

基于1维Numpy数组x、 y、 z提供的三维坐标数据，绘制线

图形（1D数据）

from mayavi import mlab
import numpy as npn_mer, n_long = 6, 11
dphi = np.pi / 1000.0
phi = np.arange(0.0, 2*np.pi + 0.5*dphi, dphi)
mu = phi * n_mer
x = np.cos(mu) + (1+np.cos(n_long*mu/n_mer)*0.5)
y = np.sin(mu) + (1+np.cos(n_long*mu/n_mer)*0.5)
z = np.sin(n_long * mu / n_mer) * 0.5l = mlab.plot3d(x, y, z, np.sin(mu), tube_radius = 0.025, colormap = 'Spectral')
mlab.show()

plot3d

`imshow()`

from mayavi import mlab
import numpy as nps = np.random.random((10, 10))img = mlab.imshow(s, colormap = 'gist_earth')
mlab.show()

imshow

`surf()`

from mayavi import mlab
import numpy as npdef f(x, y):return np.sin(x-y) + np.cos(x + y)x, y = np.mgrid[-7.:7.05:0.1, -5.:5.05:0.05]
s = mlab.surf(x, y, f)
mlab.show()

surf

contour_surf()

`contour3d()`

from mayavi import mlab
import numpy as npx, y, z = np.ogrid[-5:5:64j, -5:5:64j, -5:5:64j]
scalars = x*x + y*y + z*zobj = mlab.contour3d(scalars, contours=8, transparent=True)
mlab.show()

contour3d

`quiver3d()`

import numpy as np
from mayavi import mlabx, y, z = np.mgrid[-2:3, -2:3, -2:3]
r = np.sqrt(x ** 2 + y ** 2 + z ** 4)
u = y * np.sin(r)/(r + 0.001)
v = -x * np.sin(r)/(r+0.001)
w = np.zeros_like(z)obj = mlab.quiver3d(x, y, z, u, v, w, line_width=3, scale_factor=1)
mlab.show()