配置SpringMVC的init-param标签时的错误cvc-complex-type.2.4.a

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配置web.xml中dispatcherServlet的初始化上下文路径时，出现如下错误：

配置文件信息如下：

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 <!--配置分发器DispatcherServlet -->  
 <servlet>  
     <servlet-name>dispatcherContext</servlet-name>  
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
     <load-on-startup>1</load-on-startup></span>  
     <init-param><!--这里出现报错信息-->  
         <param-name>contextConfigLocationServlet</param-name>  
         <param-value>/xxxxxxxxx/dispatcherContext-servlet.xml</param-value>  
     </init-param></span>  
 </servlet>  
 <servlet-mapping>  
     <servlet-name>dispatcherContext</servlet-name>  
     <url-pattern>/</url-pattern>  
 </servlet-mapping>  

将<init-param></init-param>标签对和<load-on-startup></load-on-startup>标签对顺序调换一下就可以了：

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 <servlet>  
     <servlet-name>dispatcherContext</servlet-name>  
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>  
     <init-param>  
         <param-name>contextConfigLocationServlet</param-name>  
         <param-value>/xxxxxxxx/dispatcherContext-servlet.xml</param-value>  
     </init-param></span>  
 <load-on-startup>1</load-on-startup></span>  
 </servlet>  
 <servlet-mapping>  
     <servlet-name>dispatcherContext</servlet-name>  
     <url-pattern>/</url-pattern>  
 </servlet-mapping>  