HDU1702 ACboy needs your help again!(队列和栈)

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题目：

ACboy needs your help again!

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6094 Accepted Submission(s): 3197

Problem Description

ACboy was kidnapped!!
he miss his mother very much and is very scare now.You can't image how dark the room he was put into is, so poor :(.
As a smart ACMer, you want to get ACboy out of the monster's labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can't solve my problems, you will die with ACboy."
The problems of the monster is shown on the wall:
Each problem's first line is a integer N(the number of commands), and a word "FIFO" or "FILO".(you are very happy because you know "FIFO" stands for "First In First Out", and "FILO" means "First In Last Out").
and the following N lines, each line is "IN M" or "OUT", (M represent a integer).
and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully!

Input

The input contains multiple test cases.
The first line has one integer,represent the number oftest cases.
And the input of each subproblem are described above.

Output

For each command "OUT", you should output a integer depend on the word is "FIFO" or "FILO", or a word "None" if you don't have any integer.

Sample Input

  4
4 FIFO
IN 1
IN 2
OUT
OUT
4 FILO
IN 1
IN 2
OUT
OUT
5 FIFO
IN 1
IN 2
OUT
OUT
OUT
5 FILO
IN 1
IN 2
OUT
IN 3
OUT

Sample Output

Source

2007省赛集训队练习赛（1）

代码：

#include <stdio.h>
#include <stack>
#include <cstring>
#include <queue>
using namespace std;
int main()
{int t;scanf("%d",&t);//数据的组数while(t--){int n;queue<int> q;//先声明一个队列和一个栈stack<int> s;char str[10];scanf("%d %s",&n,str);if(strcmp(str,"FIFO")==0)//判断输入要求的是队列{while(n--)//指令的组数{char zl[10];int x;scanf("%s",zl);if(strcmp(zl,"IN")==0){scanf("%d",&x);q.push(x);//如果是输入的指令，就把输入的值加入队列}else if(strcmp(zl,"OUT")==0)//如果是出的指令{if(!q.empty())//当队列非空时{printf("%d\n",q.front());//打印队首，并抛弃队首元素q.pop();}else{printf("None\n");}}}}else if(strcmp(str,"FILO")==0)//判断输入要求的是栈{while(n--)//命令的组数{char zl[10];int x;scanf("%s",zl);if(strcmp(zl,"IN")==0){scanf("%d",&x);s.push(x);//如果是输入的指令，就把输入的值加入栈}else if(strcmp(zl,"OUT")==0){if(!s.empty())//当栈非空时{printf("%d\n",s.top());//打印栈顶元素，并出栈s.pop();}else{printf("None\n");}}}}}return 0;
}

PS:队列和栈的一道很简单的练习题，帮助理解概念

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