Angle Between Hands of a Clock

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Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand.

Answers within 10-5 of the actual value will be accepted as correct.

Example 1:

Input: hour = 12, minutes = 30
Output: 165

思路：算hourhand和minhand，

// 12 hours -> 360; => 1 hour -> 30, 60 min -> 30;
// 60 mins -> 360;
// hour里面对应的min度数 是跟min里面对应的度数是不一样的
 //  时钟指针60min对应的是30度；
// 分针指针60min对应的是360度；

class Solution {public double angleClock(int hour, int minutes) {// 12 hours -> 360; => 1 hour -> 30, 60 min -> 30;// 60 mins -> 360;// hour里面对应的min度数 是跟min里面对应的度数是不一样的//  时钟指针60min对应的是30度；// 分针指针60min对应的是360度；double hourAngle = hour * (360 / 12) + minutes * ((double)30 / 60);double minAngle = minutes * (360 / 60);double diff = Math.abs(hourAngle - minAngle);return diff > 180 ? 360 - diff : diff;}
}

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