链表（篇5）用链表实现多项式相加

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使用链接实现两个多项式相加

例：

输入：第一数= 5x ^ 2 + 4x ^ 1 + 2x ^ 0第二数= 5x ^ 1 + 5x ^ 0
输出：5x ^ 2 + 9x ^ 1 + 7x ^ 0
输入：第一数= 5x ^ 3 + 4x ^ 2 + 2x ^ 0第二数= 5x ^ 1 + 5x ^ 0
输出：5x ^ 3 + 4x ^ 2 + 5x ^ 1 + 7x ^ 0

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代码

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// C++ program for addition of two polynomials
// using Linked Lists
#include<bits/stdc++.h>
using namespace std;// Node structure containing power and coefficient of variable
struct node
{int coeff;int pow;struct node *next;
};// Function to create new node
void create_node(int x, int y, struct node **temp)
{struct node *r, *z;z = *temp;if(z == NULL){r =(struct node*)malloc(sizeof(struct node));r->coeff = x;r->pow = y;*temp = r;r->next = (struct node*)malloc(sizeof(struct node));r = r->next;r->next = NULL;}else{r->coeff = x;r->pow = y;r->next = (struct node*)malloc(sizeof(struct node));r = r->next;r->next = NULL;}
}// Function Adding two polynomial numbers
void polyadd(struct node *poly1, struct node *poly2, struct node *poly)
{
while(poly1->next && poly2->next){// If power of 1st polynomial is greater then 2nd, then store 1st as it is// and move its pointerif(poly1->pow > poly2->pow){poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 = poly1->next;}// If power of 2nd polynomial is greater then 1st, then store 2nd as it is// and move its pointerelse if(poly1->pow < poly2->pow){poly->pow = poly2->pow;poly->coeff = poly2->coeff;poly2 = poly2->next;}// If power of both polynomial numbers is same then add their coefficientselse{poly->pow = poly1->pow;poly->coeff = poly1->coeff+poly2->coeff;poly1 = poly1->next;poly2 = poly2->next;}// Dynamically create new nodepoly->next = (struct node *)malloc(sizeof(struct node));poly = poly->next;poly->next = NULL;}
while(poly1->next || poly2->next){if(poly1->next){poly->pow = poly1->pow;poly->coeff = poly1->coeff;poly1 = poly1->next;}if(poly2->next){poly->pow = poly2->pow;poly->coeff = poly2->coeff;poly2 = poly2->next;}poly->next = (struct node *)malloc(sizeof(struct node));poly = poly->next;poly->next = NULL;}
}// Display Linked list
void show(struct node *node)
{
while(node->next != NULL){printf("%dx^%d", node->coeff, node->pow);node = node->next;if(node->next != NULL)printf(" + ");}
}// Driver  program
int main()
{struct node *poly1 = NULL, *poly2 = NULL, *poly = NULL;// Create first list of 5x^2 + 4x^1 + 2x^0create_node(5,2,&poly1);create_node(4,1,&poly1);create_node(2,0,&poly1);// Create second list of 5x^1 + 5x^0create_node(5,1,&poly2);create_node(5,0,&poly2);printf("1st Number: "); show(poly1);printf("\n2nd Number: ");show(poly2);poly = (struct node *)malloc(sizeof(struct node));// Function add two polynomial numberspolyadd(poly1, poly2, poly);// Display resultant Listprintf("\nAdded polynomial: ");show(poly);return 0;
}

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output：

1st Number: 5x^2 + 4x^1 + 2x^0
2nd Number: 5x^1 + 5x^0
Added polynomial: 5x^2 + 9x^1 + 7x^0

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