本文主要是介绍100的红包7个人随机分，限制值在10-30之间，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！
public class RedPacketTest {public static void main(String[] args) {for (int i = 0; i < 5; i++) {splitRedPacket(100.00, 7, 10.0, 30.0);}}/*** 每个数由最小值加上随机数，每次生成随机数由剩余的数减去随机数** @param total 总和* @param splitCount 分割的个数* @param min 最小值* @param max 最大值*/public static void splitRedPacket1(Double total, int splitCount, Double min, Double max) {Double left = Double.parseDouble("" + (total - splitCount * min));Random random = new Random();DecimalFormat dcmFmt = new DecimalFormat("0.00");Double num;ArrayList<Double> list = new ArrayList<>();do {num = random.nextFloat() * left;if (num < max - min && num > 0) {//在差值之间splitCount--;if (splitCount == 0) {num = left;}list.add(Double.parseDouble(dcmFmt.format(num + min)));left = Double.parseDouble(dcmFmt.format(left - num));}} while (splitCount != 0);//随机排序Collections.shuffle(list);System.out.println(Arrays.toString(list.toArray()));Double sum = 0.0;for (double x : list) {sum = sum + x;}System.out.println("验证总和：" + dcmFmt.format(sum));}/*** 判断个数奇偶，奇数先生成一个，剩下的配对，求出各队的总和，先随机生成一个，后由总数减去随机数** @param total* @param splitCount* @param min* @param max*/public static void splitRedPacket(Double total, int splitCount, Double min, Double max) {ArrayList<Double> al = new ArrayList<>();Random random = new Random();DecimalFormat dcmFmt = new DecimalFormat("0.00");// 奇数个红包，需要单独将其中一个红包先生成，以保证后续算法拆分份数为偶数。if ((splitCount & 1) == 1) {Double num = 0.0;do {num = random.nextDouble() * max;} while (num >= max || num <= min);total = Double.parseDouble(dcmFmt.format(total - num));al.add(Double.parseDouble(dcmFmt.format(num)));}int couples = splitCount >> 1;Double perCoupleSum = total / couples;perCoupleSum = Double.parseDouble(dcmFmt.format(perCoupleSum));for (int i = 0; i < couples; i++) {Double num1 = 0.0;Double num2 = 0.0;do {num1 = random.nextDouble() * max;num2 = Double.parseDouble(dcmFmt.format(perCoupleSum - num1));if (!al.contains(num1) && !al.contains(num2)) {if (i == 0) {num1 = (total - couples * perCoupleSum) + num1;}}} while (num1 < min || num1 > max || num2 < min || num2 > max);al.add(Double.parseDouble(dcmFmt.format(num1)));al.add(Double.parseDouble(dcmFmt.format(num2)));}System.out.println("------------" + Arrays.toString(al.toArray()));Double check_num = 0.0;for (Double x : al) {check_num = check_num + x;}System.out.println("验证总和：" + dcmFmt.format(check_num));}}
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