复数计算 [(8+6i)*(4+3i)]/[(8+6i)+(4+3i)]= ?

2024-06-20 09:08

文章标签 计算复数 3i 6i

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计算复数 [(8+6i)*(4+3i)]/[(8+6i)+(4+3i)]= ?
复数运算规则详见百度百科

/** @Author: jinbo.ma* @Mail: 18710648068@163.com* @Date: 2021-03-11 15:02:21* @LastEditTime: 2021-03-13 16:50:20*/#include <stdio.h>typedef struct complex {double real, imag;
} complex;void create (complex *reslut, double real, double imag) {reslut->real = real;reslut->imag = imag;
}void add (complex *reslut, complex a, complex b) {reslut->real = a.real + b.real;reslut->imag = a.imag + b.imag;
}void sub (complex *reslut, complex a, complex b) {reslut->real = a.real - b.real;reslut->imag = a.imag - b.imag;
}void multiply (complex *reslut, complex a, complex b) {reslut->real = a.real * b.real - a.imag * b.imag;reslut->imag = a.imag * b.real + a.real * b.imag;
}int div (complex *reslut, complex a, complex b) {double tmp = b.real * b.real + b.imag * b.imag;printf("tmp=%f\n", tmp);if ( tmp == 0.0 ) {return -1; //div by zero}printf ("%f\n", a.real * b.real + a.imag * b.imag);printf ("%f\n", a.imag * b.real - a.real * b.imag);reslut->real = (a.real * b.real + a.imag * b.imag)/tmp;reslut->imag = (a.imag * b.real - a.real * b.imag)/tmp;return 0; //success
}/*** complex [(8+6i)*(4+3i)]/[(8+6i)+(4+3i)]= ?* mul=14.000000 + 48.000000i* sum=12.000000 + 9.000000i* tmp=225.000000* 600.000000* 450.000000* res=2.666667(或8/3) + 2.000000i
*/
int main (int argc, char **argv) {complex a, b, mul, sum, res;create (&a, 8, 6);create (&b, 4, 3);multiply (&mul, a, b);printf ("mul=%f + %fi\n", mul.real, mul.imag);add (&sum, a, b);printf ("sum=%f + %fi\n", sum.real, sum.imag);int ret = div (&res, mul, sum);if ( ret == -1 ) {printf ("div by zero!");} else {printf ("res=%f + %fi\n", res.real, res.imag);}return 0;
}