【Leetcode 38】报数

本文主要是介绍【Leetcode 38】报数，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

题目描述

补充说明一下题目的意思

解法一：

class Solution:def countAndSay(self, n: int) -> str:prev_person = '1'for i in range(1,n):next_person, num, count = '', prev_person[0], 1for j in range(1,len(prev_person)):if prev_person[j] == num:count += 1else:next_person += str(count) + numnum = prev_person[j]count = 1next_person += str(count) + numprev_person = next_personreturn prev_person

参考链接
https://leetcode-cn.com/problems/count-and-say/solution/ji-su-jie-bu-di-gui-zhi-ji-lu-qian-hou-liang-ren-p/

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