最小产品价格差值

本文主要是介绍最小产品价格差值，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

题目描述

给定某产品多少天的价格，记录于prices中，请找出任意两天之间的最小价格差（即abs(prices[i] - prices[j])）的最小值，i!=j）并计算最小介个差组合的个数

样例1

输入

[1,3,7,5,12]

输出

3

样例2

输入

[90,98,90,90,1,1]

输出

4

Java源码

import java.nio.charset.StandardCharsets;
import java.util.Scanner;public class MinPriceDiff {public static void main(String[] args) {Scanner cin = new Scanner(System.in, StandardCharsets.UTF_8.name());while (cin.hasNext()) {String[] inputStr = cin.nextLine().split(",");int[] prices = new int[inputStr.length];for (int i = 0; i < inputStr.length; i++) {prices[i] = Integer.parseInt(inputStr[i]);}System.out.println(getMinPriceDiff(prices));}}static int getMinPriceDiff(int[] prices) {int n = prices.length;// 最小差值int minDiff = Integer.MAX_VALUE;// 最小差值组数int count = 0;for (int i = 0; i < n; i++) {for (int j = i + 1; j < n; j++) {// 差值int diff = Math.abs(prices[i] - prices[j]);// 若果差值小于最小差值计数初始化为1if (diff < minDiff) {minDiff = diff;count = 1;} else if (diff == minDiff) {// 如果差值等于最小差值则计数+1count++;}}}return count;}
}

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