E题:Digit Sum Divisible 标签:数位 d p dp dp题意:给定一个 n n n,求小于等于 n n n的数中有多少个能被自己的位数之和整除。( 1 < = n < = 1 0 14 1<=n<=10^{14} 1<=n<=1014)**题解:**数位 d p dp dp模版题, d p [ p o s ] [ s u m ] [ m o d ] dp[pos][sum][
Problem Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example1 In