思路: 无源汇 (附加源汇+最大解决) 有源汇 (附加(T,S)->无源汇) Budget Time Limit: 3000MS Memory Limit: 65536KTotal Submissions: 6237 Accepted: 2367 Special Judge Description We are supposed to make
这道题是对有上下界网络流问题的第一次实践。这题不需要求最大流或最下流,只要判断是否存在可行流,如果存在输出这个可行流(根据题目中的这句话判断:And, by the way, no one really reads budget proposals anyway, so we'll just have to make sure that it sums up properly and
一开始想了个fft 时间复杂度 O(t∗n2log n2) O ( t ∗ n 2 l o g n 2 ) O( t * n^2 log\ {n^2}) 应该超时了… 然后看了题解… 随机化… c++代码如下: #include<bits/stdc++.h>#define rep(i,x,y) for(register int i = x ; i <= y; ++ i)#defin