byte b = 130;有没有问题?,(有)。如果我想让赋值正确,可以怎么做(强制类型转换,截取最低一个字节)?结果是多少呢? 源代码: class Test {public static void main(String[] args) {// 因为byte的范围是:-128到127。(-2^7--2^7-1)// 而130不在此范围内,所以报错。// byte b = 130;//
题目: 题解: class Solution:def solve(self, board: List[List[str]]) -> None:if not board:returnn, m = len(board), len(board[0])que = collections.deque()for i in range(n):if board[i][0] == "O":que.appen
题目: Given a 2D board containing 'X' and 'O', capture all regions surrounded by 'X'. A region is captured by flipping all 'O's into 'X's in that surrounded region. For example, X X X XX O O X
LeetCode第130周周赛问题基本不难。 1017. Convert to Base -2 这个问题类似于十进制求二进制表达的过程,但因为是负数,需要做一些处理,数学证明这里不赘述,参考 class Solution {public String baseNeg2(int N) {int remainder=N%(-2);N/=(-2);if(remainder<0){remainder+=
class Solution {public:int rows, columns;void solve(vector<vector<char>>& board) {rows = board.size();columns = board[0].size();for(auto i = 0; i < rows; ++i){dfs(board, i, 0); //左边界dfs(board, i, c
解题思路: 深度优先搜索(dfs) 数位之和的表示方法: int sums(int x)int s = 0;while(x != 0) {s += x % 10;x = x / 10;}return s; 题解: class Solution {int m, n, cnt;boolean[][] visited;public int wardrobeFinishing(int m,