题目： 题解： int evalRPN(char** tokens, int tokensSize) {int n = tokensSize;int stk[(n + 1) / 2];memset(stk, 0, sizeof(stk));int index = -1;for (int i = 0; i < n; i++) {char* token = tokens[i];if (strl

题目： 题解： class Solution:def evalRPN(self, tokens: List[str]) -> int:op_to_binary_fn = {"+": add,"-": sub,"*": mul,"/": lambda x, y: int(x / y), # 需要注意 python 中负数除法的表现与题目不一致}n = len(tokens)stack =

题目： 题解： class Solution {public:int evalRPN(vector<string>& tokens) {int n = tokens.size();vector<int> stk((n + 1) / 2);int index = -1;for (int i = 0; i < n; i++) {string& token = tokens[i];if (to