递归反转单链表(头插法反转部分链表 要弄pre cur 还有nxt(临时变量保存下一个结点 P0指到需要修改的链表的前一个结点 class Solution {public ListNode reverseBetween(ListNode head, int left, int right) {ListNode dummy=new ListNode(-1,head);ListNode p0=
Linked List Inserting a node at beginning #include<stdlib.h>//为了用malloc#include<stdio.h>struct node {int data;struct node* next;//在cpp中可以只写 Node *Link;//为了表意明确,Link也经常被命名为next};struct node* head
2-链表-51-删除链表的倒数第 N 个结点-LeetCode19 参考:代码随想录 LeetCode: 题目序号19 更多内容欢迎关注我(持续更新中,欢迎Star✨) Github:CodeZeng1998/Java-Developer-Work-Note 技术公众号:CodeZeng1998(纯纯技术文) 生活公众号:好锅(Life is more than code) CS