sell专题
Leetcode:72 Best Time to Buy and Sell Stock
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock),
leetcode122-Best Time to Buy and Sell Stock II
题目 给你一个整数数组 prices ，其中 prices[i] 表示某支股票第 i 天的价格。 在每一天，你可以决定是否购买和/或出售股票。你在任何时候 最多 只能持有 一股 股票。你也可以先购买，然后在 同一天 出售。 返回 你能获得的 最大 利润 。 示例 1： 输入：prices = [7,1,5,3,6,4] 输出：7 解释：在第 2 天（股票价格 = 1）的时候买入，在第 3 天（股
**Leetcode 123 Best Time to Buy and Sell Stock III
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iii/description/ O(n^2)的做法就不解释了，枚举划分的位置即可。但是关键点在最多两次，所以可以考虑前缀后缀和。 先说O(n^2)的 class Solution {public:int maxProfitForOne(vector<int>&
Leetcode Best Time to Buy and Sell Stock
https://leetcode.com/problems/best-time-to-buy-and-sell-stock/description/ O(n^2)的就不用说了，一层遍历start_idx 一层遍历end_idx， 所以要在O(n)时间做的话 就是一次遍历记录两个位置，特殊点在于， start_idx总是当前最小， 答案一定的在这样的解中产生，就是 当前值减去当前最小值。
*** Leetcode 309. Best Time to Buy and Sell Stock with Cooldown | dp
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-with-cooldown/description/ 因为做过之前那个题，所以还是能比较快做出来的。 做法1： dp[i][0]: 第i天卖，完成i次买和卖 dp[i][1]:第i天买，完成i-1次卖和i次买 class Solution {public:int
《leetCode》：Best Time to Buy and Sell Stock III
题目 Say you have an array for which the ith element is the price of a given stock on day i.Design an algorithm to find the maximum profit. You may complete at most two transactions. 思路一：报超时错误 思路：分而治
《leetCode》：Best Time to Buy and Sell Stock II
题目 Say you have an array for which the ith element is the price of a given stock on day i.Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy o
LeetCode 121. Best Time to Buy and Sell Stock
121. Best Time to Buy and Sell Stock 一、问题描述 Say you have an array for which the i*th element is the price of a given stock on day *i. If you were only permitted to complete at most one transaction
51.Best Time to Buy and Sell Stock（动态规划）
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock),
50.Best Time to Buy and Sell Stock II(贪心算法)
题目原文： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (
LeetCode *** 121. Best Time to Buy and Sell Stock
题目： Say you have an array for which the ith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the sto
【启发】leetcode - 121. Best Time to Buy and Sell Stock 【动态规划 + 连续区间问题 + 试探性购买】
题目 Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the sto
Leetcode 123 Best Time to Buy and Sell Stock III
原题： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may n
[leetcode] 122. Best Time to Buy and Sell Stock II
这是一个非常简单贪心问题，贪心问题的解决方法一般都非常简单，但是要想到这个方法真的挺不容易的： Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may comple
leetcode121~Best Time to Buy and Sell Stock
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), d
小白水平理解面试经典题目LeetCode 121 Best Time to Buy and Sell Stock
121 Best Time to Buy and Sell Stock (买卖股票的最佳时机) 你好，2024年的第一个月，又是秋风萧瑟天气凉，草木摇落露为霜。.。。在这个特殊的时代，作为我们普通的一个打工人，我们用这道题，开启对这个不符合经济增长规律的股市反抗一把。 题目描述 有这样一个数组 prices ，其中 prices[i] 是给定股票在 ith天的价格。 我希望通过选择某一天购
leetcode-123 Best Time to Buy and Sell Stock III
此题是限制在两次交易内，相对要难一些。容易想到的解决办法是，把prices[] 分成两部分prices[0...m] 和 prices[m...length] ，分别计算在这两部分内做交易的做大收益。由于要做n次划分，每次划分可以采用 第一题： Sell Stock I的解法， 总的时间复杂度为O(n^2). <span style="font-size:14px;">public cla
LeetCode - 123. Best Time to Buy and Sell Stock III - 思路详解 - C++
题目 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. 翻译 假设一个数组，表示第i
LeetCode - 122. Best Time to Buy and Sell Stock II - 思路详解 - C++
题目 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy
LeetCode - 121. Best Time to Buy and Sell Stock - 思路详解 - C++
题目 Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock
LeetCode121 Best Time to Buy and Sell Stock
题目要求: 121. Best Time to Buy and Sell Stock QuestionEditorial Solution My Submissions Total Accepted: 139457Total Submissions: 364702Difficulty: EasyContributors: AdminSay you have an array for w
Leetcode#122. Best Time to Buy and Sell Stock II
题目描述：一个数组代表每天的股票价格，你可以选择多次买入卖出，使得收益最大。需要注意的是，下一次买入之前一定要先卖出。 解题思路：其实就考虑一点，什么时候收益最大？答案是只要有利润，就进行交易。也就是说，只要下一次的价格比当前价格大，就交易。 总体来看，只要今天比前一天的价格高，就有收益，最后将这些收益累加，就是最大收益。 C++实现如下： class Solution {public:
121. Best Time to Buy and Sell Stock（Array）
##### 题目描述： Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share o
Best Time to Buy and Sell Stock 2
没有想出来，网上搜的答案。甚至搜到了答案，提交正确了，我都不知道它为什么就对了。 教训：不要把事情复杂化。 #include <iostream>using namespace std;class Solution {public:int maxProfit(vector<int> &prices) {int result = 0;int i = 0;int len = prices.