poj2533专题

Longest Ordered Subsequence-POJ2533 O(nlog(n))算法

Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 45282 Accepted: 20075 Description A numeric sequence of ai is ordered if a1 < a2 < … < aN. Let the subsequenc

poj2533纯最长上升子序列

//题意:求最长上升子序列 //思路:记录每个状态的最大值,且时刻维护最大值 #include <iostream>#include <algorithm>#include <cstdio>#include <cstring>using namespace std;int num[1000+10];int dp[1000+10];int main(){int n;while(scan