parentheses专题

856. Score of Parentheses

856. Score of Parentheses class Solution:def scoreOfParentheses(self, s: str) -> int:stack=[]i=0for c in s:if c=='(':stack.append(c)else:score=0while stack[-1]!='(':score+=stack.pop()stack.pop()score

leetcode#32. Longest Valid Parentheses

题目 Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. For "(()", the longest valid parentheses substring is "()", wh

LeetCode - 32. Longest Valid Parentheses

32. Longest Valid Parentheses  Problem's Link  ---------------------------------------------------------------------------- Mean:  给定一个由'('和')'组成的字符串,求最长连续匹配子串长度. analyse: 定义一个stack<pair

LeetCode 22 Generate Parentheses

题意: 用n组小括号,生成所有满足括号匹配的序列。 思路: 我用了比较粗暴的方式,用set不断迭代答案,每次迭代使得括号组数+1直到n为止。 还有一种方法是dfs构造,因为长度已经确定,所以每个位置要么放(要么放),利用前缀和维护括号匹配即可。 代码: class Solution {public:vector <string> generateParenthesis

Leetcode90: Generate Parentheses

Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: "((()))", "(()())", "(())()", "()(())", "()()(

LeetCode第21题之Generate Parentheses(两种解法)

C++代码: 解法一(在LeetCode上运行效率高于解法二): #include <vector>#include <iostream>#include <string>using namespace std;class Solution {private:vector<string> res;public: //leftRemain保存还可以放左括号的数目,rightRemain

LeetCode第20题之Valid Parentheses

方法一:用栈实现 C++代码: #include <stack>#include <iostream>using namespace std;//Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.clas

Easy 5 Valid Parentheses(20)

Description Given a string containing just the characters ‘(‘, ‘)’, ‘{‘, ‘}’, ‘[’ and ‘]’, determine if the input string is valid. The brackets must close in the correct order, “()” and “()[]{}” are

leetcode-32. Longest Valid Parentheses

leetcode-32. Longest Valid Parentheses Given a string containing just the characters ‘(’ and ‘)’, find the length of the longest valid (well-formed) parentheses substring. For “(()”, the longest val

leetcode No20. Valid Parentheses

C++中栈(stack)的用法 s.empty() //如果栈为空返回true,否则返回false s.size() //返回栈中元素的个数 s.pop() //删除栈顶元素但不返回其值 s.top() //返回栈顶的元素,但不删除该元素 s.pus

[LeetCode] Remove Invalid Parentheses

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other than the parentheses ( and ).

LeetCode 题解(151): Different Ways to Add Parentheses

题目: Given a binary search tree, write a function kthSmallest to find the kth smallest element in it. Note:  You may assume k is always valid, 1 ≤ k ≤ BST's total elements. Follow up: What if t

LeetCode 题解(150): Different Ways to Add Parentheses

题目: Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +, - and *. Examp

**Leetcode 32. Longest Valid Parentheses

主要两种思路,stack 以及 dp 我想出来的是stack的solution 自己的Dp没A掉,看了别人的Dp思路才懂。 1、最简单易懂的 struct Node {int idx;char c;Node(int idx, char c): idx(idx), c(c) {}};class Solution {public:int match(char l, char r) {if

generate Parentheses----leetcode

1.和valid parentheses不一样,valid那个题,只需要遍历序列,当遇到序列的左括号,则入栈,遇到序列的右括号查看栈顶元素是否为左括号可以和当前右括号匹配,如果可以,则将这个栈顶元素(左括号)删除;当遍历完序列后,如果栈为空,则序列是有效的,否则序列是无效的。 2.这个题开始以为和华为oj上的火车进站一样,求序列符号的全排列,后来run code了一发发现不是,好惨。找到了一篇文

balance parentheses

题目: Given a string with parentheses, return a string with balanced parentheses  by removing the fewest characters possible. You cannot add anything to the string. Examples: balance("()") -> "()" bala

[LeetCode] 32. Longest Valid Parentheses @ python

一.题目: 找出一个只包含"(“和”)"的字符串中最长的有效子字符串的长度。有效的意思是指该子字符串中的括号都能正确匹配。 Example 1: Input: "(()"Output: 2Explanation: The longest valid parentheses substring is "()" Example 2: Input: ")()())"Output: 4Ex

leetcode -- 22. Generate Parentheses faster than 100%

题目描述 Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ “((()))”, “(()())”, “(())()”, “()(())”, “

leetcode -- 20. Valid Parentheses

题目描述 Given a string containing just the characters ‘(’, ‘)’, ‘{’, ‘}’, ‘[’ and ‘]’, determine if the input string is valid. An input string is valid if: Open brackets must be closed by the same typ

leetcode 241:Different Ways to Add Parentheses

Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +,- and *. 题目分析:看到这个题,第一反应竟

LeetCode [栈] 20.Valid Parentheses (C++和Python实现)

20 Valid Parentheses [难度:简单] [括号匹配] 【题目】 Given a string containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid. An input string is valid if: Open br

【Leetcode】【240406】1249. Minimum Remove to Make Valid Parentheses

其实大部分是东京时间第二天凌晨才做的- -但国际服刷新比较晚 BGM:刀剑如梦 Decsripition Given a string s of ‘(’ , ‘)’ and lowercase English characters. Your task is to remove the minimum number of parentheses ( ‘(’ or ‘)’, in any po

Parentheses Matrix —— 枚举+模拟

Problem Description A parentheses matrix is a matrix where every element is either ‘(’ or ‘)’. We define the goodness of a parentheses matrix as the number of balanced rows (from left to right) and c

LeetCode第20题 有效的括号(Valid Parentheses)

文章目录 题目地址题目描述代码实现 题目地址 题目地址https://leetcode-cn.com/problems/valid-parentheses/ 题目描述 给定一个只包括 ‘(’,’)’,’{’,’}’,’[’,’]’ 的字符串,判断字符串是否有效。 有效字符串需满足: 左括号必须用相同类型的右括号闭合。左括号必须以正确的顺序闭合。 注意空字符串可被认为是

suggest parentheses around assignment used as truth value [-Wparentheses]

这个编译器警告表明,在被用作条件表达式的赋值语句周围可能缺少括号。编译器提醒你,赋值操作在条件判断中可能会造成歧义或者是个错误。这种警告是良好编程实践的一部分,旨在帮助开发者避免犯易错的编程错误。 例如,考虑下面的 C 代码: if (a = b) {// ...} 这里的意图可能是比较 a 和 b 的值: if (a == b) {// ...} 但实际上,a = b 是一个赋

uva 673 Parentheses Balance

原题: You are given a string consisting of parentheses () and []. A string of this type is said to be correct: (a) if it is the empty string (b) if A and B are correct, AB is correct, (c) if A is co