lists专题

leetcode-23Merge k Sorted Lists

带头结点。 /*** Definition for singly-linked list.* public class ListNode {* int val;* ListNode next;* ListNode(int x) { val = x; }* }*/public class Solution {public ListNode mergeKLists

Leetcode43: Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 用归并排序的思想。 /*** Definition for singly-linked list.* str

23. Merge k Sorted Lists 优先队列比较器

把k个有序链表merge成一个有序的链表 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 使用优先队列，先把所有不为空的链表头放到优先队列中，然后将最大的一个poll()出来，如果这个最大的节点再原链表中有下一个节点那么把它的下一个节点放

(LeetCode)Merge Two Sorted Lists --- 合并两个有序序列

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 解题分析: 对于此题目，应该先加一个头结点，然后依次比较两个有序的 list 然后将比较，将小的连接

ARTS leetcode7 Merge Two Sorted Lists

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.Example:Input: 1->2->4, 1->3->4Output: 1->1->2->3->4->4

ubuntu E: 无法获得锁 /var/lib/apt/lists/lock - open (11: 资源暂时不可用)

ubuntu E: 无法获得锁 /var/lib/apt/lists/lock - open (11: 资源暂时不可用) 今天使用三丰云免费云服务器的时候，又遇到奇葩问题，对于别人来说可能特别简单，但是我是个小白，没有学习过linux，所有问题全靠上网搜索。之前一直用笔记本搭建的服务器，但是24小时开机太费电了，外网访问也是问题，现在用上三丰云的免费服务器太爽了，性能杠杠滴。够我这种初学者用

[AIGC] 使用Google的Guava库中的Lists工具类：常见用法详解

在Java程序设计中，集合是我们最常用的数据结构之一。为了方便我们操作集合，Google的Guava库提供了一个名为Lists的工具类，它封装了许多用于操作List对象的实用方法。在本文中，我们将详细介绍其常见的用法，以帮助您更好地理解和运用此工具类。文章目录 1. `Lists.newArrayList()`2. `Lists.partition(List list, i

LeetCode第23题之Merge k Sorted Lists

楼主是参考：http://www.cnblogs.com/skysand/p/4300711.html，感觉这篇博客写得挺好的。 C++代码： #include <vector>#include <iostream>#include <algorithm>using namespace std;/*** Definition for singly-linked list. */struc

【捷哥浅谈PHP】第二十弹---NoSQL数据库Redis之青干剑(lists类型)的修炼

今天来看我们的Redis神器的第三把剑，青干剑（lists类型）的修炼：第三把----------------------青干剑（lists类型）介绍：List 是一个链表结构，主要功能是push、pop、获取一个范围的所有值等等，操作中key理解为链表的名字。Redis的list类型其实就是一个每个子元素都是string类型的双向链表。我们可以通过push、pop操作从链表的头

Easy 6 Merge Two Sorted Lists（21）

Description Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Solution 将两个有序链表合并成一个链表。（定义一个头结点，方便返回） /**

Merge Two Sorted Lists(和并两个从小到大排好序的链表)

描述： Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析：如果第一个链表为空，则返回第二个链表如果第二个链表为空，就返回第一个链表（都为空会返回空

leetcode No160. Intersection of Two Linked Lists

Question: Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2↘c1 → c2 → c3↗

leetcode oj java 23. Merge k Sorted Lists

一、问题描述： Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Subscribe to see which companies asked this question 二、解决思路： Merge k Sorted Lists 属于

Merge 2 Sorted Lists

合并两个有序链表： P1 1-3-5-7-9 P2 2-4-6-8-10 首先选取P1.head 和P2.head 中较小的作为头结点。假设是P1. 那么Head的next节点应该是P1.next 和 p2 中较小的节点。即P1以P1.next 为头结点继续迭代。代码（递归） public static ListNode mergeLists(ListNode r1,

LeetCode 题解(216) : Intersection of Two Linked Lists

题目： Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2↘c1 → c2 → c3↗ B:

[LeetCode] 160. Intersection of Two Linked Lists

题目内容 https://leetcode-cn.com/problems/intersection-of-two-linked-lists/ Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two

[leetcode-排序]--23. Merge k Sorted Lists

Question 23. Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 中文：合并k个有序的链表，然后返回一个有序的链表的表头结点。解决思路： 1) 模仿两个链表的做法：用一个链表数组Li

[leetcode-排序]--21. Merge Two Sorted Lists

Question 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 中文：合并两个有序的链表，然后返回新的链

《leetCode》：Merge Two Sorted Lists

题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思想比较简单：利用两个指针遍历两个链表，并比较将较小的值进行保存。实现代码如下： /*** Def

Lists.partition用法详解

文章目录一、引入依赖二、用法三、输出一、引入依赖依赖于谷歌的guava 包 <dependency><groupId>com.google.guava</groupId><artifactId>guava</artifactId><version>28.1-jre</version></dependency> 二、用法将strings整

49.Intersection of Two Linked Lists

Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2↘c1 → c2 → c3↗ B: b1

LeetCode--160. Intersection of Two Linked Lists

Problem: Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2↘c1 → c2 → c3↗

Merge Two Sorted Lists - LeetCode

Merge Two Sorted Lists - LeetCode 题目： Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析：我选择的方式是

LeetCode 21. Merge Two Sorted Lists 合并两个有序单链表

合并两个排好序的链表，并返回这个新的有序链表。 Java package com.linkedlist;/*** @Author you guess* @Date 2022/4/2 23:01* @Version 1.0* @Desc */public class Leetcode_21_MergeTwoSortedLists {public static void main(String[

访问控制列表（Access Control Lists, ACL）

访问控制列表（Access Control Lists, ACL）在网络管理中扮演着至关重要的角色，其主要作用包括但不限于以下几个方面：安全控制： ACL能够根据预定义的规则允许或拒绝网络流量。管理员可以根据源IP地址、目的IP地址、协议类型（如TCP、UDP、ICMP等）、端口号以及更多的字段来制定规则，确保只有合法或授权的通信才能通过网络设备，阻止非法或非必要的访问请求。流量过滤：通

104.Merge k Sorted Lists-合并k个排序链表（中等题）

合并k个排序链表题目合并k个排序链表，并且返回合并后的排序链表。尝试分析和描述其复杂度。样例给出3个排序链表[2->4->null,null,-1->null]，返回 -1->2->4->null题解先遍历删除空链表，再循环遍历头结点，最小值出列，直至只剩一条链表直接接入到排序链表尾部。 /*** Definition for ListNode.* public class Li