题目链接:hdu 5578 Friendship of Frog 代码 #include <cstdio>#include <cstring>#include <algorithm>using namespace std;const int maxn = 1005;const int inf = 0x3f3f3f3f;char str[maxn];int main () {int ca
Judge Info Memory Limit: 65536KBCase Time Limit: 3000MSTime Limit: 3000MSJudger: Normal Description 青蛙们发现在传输信件时经常会被别人偷看,愤怒的青蛙向码农们求救。于是,码农们为它们提供了一套加密和解密的方法,从而将它们的信件内容加密成一段莫尔斯电码。现在给出译码程序:0.加密序列为:
The Frog Prince [青蛙王子] and Hello Kitty 1. Hello Kitty.gif2. The Frog Prince (青蛙王子) .gifReferences 1. Hello Kitty.gif Hello Kitty, also known by her real name Kitty White, is a fictional cha
题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=5924 Mr. Frog’s Problem Problem Description One day, you, a clever boy, feel bored in your math class, and then fall asleep without your control. In y
正题 CF751D 题目大意 现在有n个点,当你在i时,可以向前跳 0 ∼ a i 0\sim a_i 0∼ai 步,跳到j,然后向后走 b j b_j bj步,现在让你从n开始跳,回答跳到0的最少步数 解题思路 设 f i f_i fi为跳到i的最少步数,每次转移先减 b i b_i bi然后再转移 求最小值可以用线段树优化 时间复杂度 O ( n l o g
LeetCode刷题:403. Frog Jump 青蛙过河问题JAVA算法设计 A frog is crossing a river. The river is divided into x units and at each unit there may or may not exist a stone. The frog can jump on a stone, but it must n
题目描述 动态规划组成部分一:确定状态 子问题 动态规划组成部分二:转移方程 动态规划组成部分三:初始条件和边界情况 动态规划四:计算顺序 Java代码实现 public boolean canCross(int[] stones) {int n = stones.length;boolean[][] f = new boolean[n][n];f[0