duplicates专题

442. Find All Duplicates in an Array 找数组中重复的数

https://leetcode-cn.com/problems/find-all-duplicates-in-an-array/description/ 题意：找出数组中所有重复的元素思路1:先将数组排序,然后判断是否重复,即若nums[i] != nums[i+1],即说明nums[i]非重复元素,可以删去. 重点在于指针(迭代器)的操作,由于vector的erase(删除)操作需要通

【Pandas驯化-04】Pandas中drop_duplicates、describe、翻转操作

【Pandas驯化-04】Pandas中drop_duplicates、describe、翻转操作本次修炼方法请往下查看 🌈 欢迎莅临我的个人主页 👈这里是我工作、学习、实践 IT领域、真诚分享踩坑集合，智慧小天地！ 🎇 相关内容文档获取微信公众号 🎇 相关内容视频讲解 B站 🎓 博主简介：AI算法驯化师，混迹多个大厂搜索、推荐、广告、数据分析、数据挖掘岗位个人申请

LeetCode 题解（160）: Remove Duplicates from Sorted List II

题目： Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Given 1-

leetcode82-Remove Duplicates from Sorted List II

题目给定一个已排序的链表的头 head ，删除原始链表中所有重复数字的节点，只留下不同的数字。返回已排序的链表。示例 1：输入：head = [1,2,3,3,4,4,5] 输出：[1,2,5] 分析要删除重复元素肯定要有一个结点标示被删除元素的前驱，所以还是用一个哨兵结点next指向头结点，然后遍历链表即可。用cur指针指向链表的头结点，然后不断比较cur和她的next结点

《leetCode》：Remove Duplicates from Sorted Array II

题目描述 Follow up for "Remove Duplicates":What if duplicates are allowed at most twice?For example,Given sorted array nums = [1,1,1,2,2,3],Your function should return length = 5, with the first five e

《leetCode》：Remove Duplicates from Sorted Array

题目描述 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this in place wi

《leetCode》：Remove Duplicates from Sorted List

题目 Given a sorted linked list, delete all duplicates such that each element appear only once.For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 题目大意：将所有不同的节点连接起来，即每个节点仅出现一

《leetCode》：Remove Duplicates from Sorted List II

题目 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.For example,Given 1->2->3->3->4->4->5, return 1->2->5.Given 1->1->

LeetCode（28）-Remove Duplicates from Sorted Array

题目： Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.Do not allocate extra space for another array, you must do this in place wit

Remove Duplicates from Sorted List - LeetCode

Remove Duplicates from Sorted List - LeetCode 题目： Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2

[leetcode]Remove Duplicates from Sorted Array

class Solution {public:int removeDuplicates(int A[], int n) {// Start typing your C/C++ solution below// DO NOT write int main() functionint len = 0;for(int i = 1; i < n; i++){if(A[i] == A[i-1]){len+

Remove Duplicates from Sorted II

题意：一个升序的数组，含有重复的元素，删除数组中重复的元素，使其最多重复两次，返回修改后数组的长度 Given sorted array A = [1,1,1,2,2,3] , Your function should return length = 5 , and A is now [1,1,2,2,3] . 思路：每次和已经记录的最后一个数组元素比较，如果重复就跳过，否则将其加入

101.Remove Duplicates from Sorted Array II-删除排序数组中的重复数字 II（容易题）

删除排序数组中的重复数字 II 题目跟进“删除重复数字”：如果可以允许出现两次重复将如何处理？样例给出数组A =[1,1,1,2,2,3]，你的函数应该返回长度5，此时A=[1,1,2,2,3]。题解解法依然是使用双指针。 public class Solution {/*** @param A: a array of integers* @return : return an

100.Remove Duplicates from Sorted Array-删除排序数组中的重复数字（容易题）

删除排序数组中的重复数字题目给定一个排序数组，在原数组中删除重复出现的数字，使得每个元素只出现一次，并且返回新的数组的长度。不要使用额外的数组空间，必须在原地没有额外空间的条件下完成。样例给出数组A =[1,1,2]，你的函数应该返回长度2，此时A=[1,2]。题解双指针法先将数组前两个元素分别用指针i和j指向，然后同时向后移动进行第一次遍历，如果nums[i] == num

LeetCode *** 80. Remove Duplicates from Sorted Array II

题目： Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first fi

leetcode:[26] Remove Duplicates from Sorted Array

题目信息如下：给定排序的数组nums，就地删除重复项，使每个元素只出现一次并返回新的长度。要求不能额外申请数组空间，只能在传入的数组中进行修改。思路：使用两个指针，一前一后进行比较，当前指针所指值比后指针大时，前后指针均向前移动一次，当前指针不比后指针大时（即两个值相等），后指针不动，前指针继续前移，直到所指值比后指针大，此时将指针值赋给后指针的下一个。重复此步骤。例

leetcode -- 26. Remove Duplicates from Sorted Array

题目描述题目难度：Easy Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must d

[leetcode]remove-duplicates-from-sorted-list

. - 力扣（LeetCode）给定一个已排序的链表的头 head ，删除所有重复的元素，使每个元素只出现一次。返回已排序的链表。示例 1：输入：head = [1,1,2]输出：[1,2] 示例 2：输入：head = [1,1,2,3,3]输出：[1,2,3] 提示：链表中节点数目在范围 [0, 300] 内-100 <= N

LeetCode 442 Find All Duplicates in an Array (思维)

Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra

leetcode83.Remove Duplicates from Sorted Lists

这个题要求删除已排好序的链表中的重复项，例如1->1->2->3->3删除之后就是1->2->3。思路是令p指向当前节点每次循环找到一个q.next.val != q.val，然后令p.next = q.next 就可以实现删除p.val对应的重复项了。 public ListNode deleteDuplicates(ListNode head) {if (head == n

LeetCode 83 Remove Duplicates from Sorted List

问题描述：解答：

LeetCode Remove Duplicates from Sorted Array I and II

题目 Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in plac

LeetCode Find All Duplicates in Array and Find Disappeared Numbers in Array

lz这里把leetcode中相同类型的两题放在一起来研究。首先是leetcode find all duplicates in array，题目如下： Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find

[LeetCode]80.Remove Duplicates from Sorted Array II

【题目】 Remove Duplicates from Sorted Array II Total Accepted: 4460 Total Submissions: 15040 My Submissions Follow up for "Remove Duplicates": What if duplicates are allowed at most twice?

[LeetCode]82.Remove Duplicates from Sorted List II

【题目】 Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Given

LeetCode 83:Remove Duplicates from Sorted List

Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 简单链表操作，代码如下： /*** Defi