Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 题目要求将有序数组转换为一个二元查找树。树的题目大部分都可以采用递归来解决,这道题也不例外。一个二元查找树的左子树上的所有节点都小于根节点,右子树上的所有节点都大于根节点,同时二元查找树左子树和右子树上
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 与排序好的数组转化为二分搜索树的题相似,可以先把链表转化为数组在转化为树。 /*** Definition for singly-linked list.* struct
Int32.Parse, Convert.ToInt32,Int32.TryParse三者的区别 Int32. Parse (string) Int32.Parse (string str) method converts the string representation of a number to its 32-bit signed integer equivalent
问题描述: Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
1、问题 /* Write a program to convert string to number without using library function。 */ 2、算法 #define MAX_LONG 0X7FFFFFFF long foo(const char* str) { int sign = 1 ; long
题目连接:Leetcode 108 Convert Sorted Array to Binary Search Tree 解题思路:每次取范围中间的数作为当前结点的值。 /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *righ
一、问题描述: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 二、解决思路: 平衡BST的话,位于中间位置的节点当做ROOT, 可以保证平衡。中间节点的左边元素为左子树右边元素为右子树,递归即可。 三、代码: package
题目: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题解: 递归。 C++版: class Solution {public:TreeNode* sortedListToBST(ListNode* head)