fmod()函数:对浮点数进行取模(求余) Example: #include <stdio.h>#include <math.h>int main (){printf ("fmod of 3.14/2.1 is %lf\n", fmod (3.14,2.1) );return 0;} Output: fmod of 3.14/2.1 is 1.04000
题目: 题解: --这道题主要考察中位数的取法SELECT category_id,cast(sum(price)/count(1) as DECIMAL(16,2)) medpricefrom(SELECTcategory_id,price,rn,max(rn)over(partition by category_id) max_rnfrom(SELECTcategory_id,pr
Numpy数组的取整函数 函数名功能numpy.ceil(x,)向正无穷取整, ⌈ x ⌉ \lceil \bm x \rceil ⌈x⌉numpy.floor(x,)向负无穷取整, ⌊ x ⌋ \lfloor \bm x \rfloor ⌊x⌋numpy.trunc/fix(x,)截取整数部分numpy.rint(x,)四舍五入到最近整数numpy.around(x,)四舍五入到给定的小数位
这个算是水题吧,就是对扩展欧几里德算法的应用题目, 题意不难,谈不上思路。 代码如下: #include <cstdio>void gcd(int a, int b, int &g, int &x, int &y){if(b==0) {g = a; x = 1; y = 0;}else {gcd(b,a%b,g,y,x); y-=x*(a/b);}}int main (){in