Nineteen

本文主要是介绍Nineteen，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

点击打开链接 http://codeforces.com/contest/393/problem/A

Alice likes word "nineteen" very much. She has a string s and wants the string to contain as many such words as possible. For that reason she can rearrange the letters of the string.

For example, if she has string "xiineteenppnnnewtnee", she can get string "xnineteenppnineteenw", containing (the occurrences marked) two such words. More formally, word "nineteen" occurs in the string the number of times you can read it starting from some letter of the string. Of course, you shouldn't skip letters.

Help her to find the maximum number of "nineteen"s that she can get in her string.

Input

The first line contains a non-empty string s, consisting only of lowercase English letters. The length of string s doesn't exceed 100.

Output

Print a single integer — the maximum number of "nineteen"s that she can get in her string.

Sample test(s) 
input 
nniinneetteeeenn
output 
2
input 
nneteenabcnneteenabcnneteenabcnneteenabcnneteenabcii
output 
2
input 
nineteenineteen
output 
2

刚开始做这道题的时候，有思路，就是建造一个int 类型的数组，标记nineteen中的4个字母，但是忽略了一个问题，就是nineteen始字母和末字母都是n，所以末尾的n也可以作为始字母n，这样就是1个nineteen有3个n，2个有5个，3个有7个，所以（b[0]-1）/2就是最大的nineteen。

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
using namespace std;
int b[5];
int main()
{string a;while(cin>>a){memset(b,0,sizeof(b));int l=a.size();for(int i=0; i<l; i++){if(a[i]=='n')b[0]++;if(a[i]=='i')b[1]++;if(a[i]=='e')b[2]++;if(a[i]=='t')b[3]++;}b[0]=(b[0]-1)/2;//根据n的数量算出最多包含"nineteen"的数量b[2]/=3;sort(b,b+4);cout<<b[0]<<endl;}return 0;
}

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