数组重载加减

本文主要是介绍数组重载加减，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

题目：

数组重载加减

2
2
5 6
3 2
3
1 2 3
3 2 1

8 8 
2 4 
4 4 4 
-2 0 2 

参考代码：

#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;
class Matrix
{
private:
int num, array[200];
public:
Matrix();
Matrix(int n, int a[200]);
Matrix(Matrix&);
Matrix operator+(const Matrix&);
Matrix operator-(const Matrix&);
void show();
};
Matrix::Matrix()
{
num = 0;
for (int i = 0; i < num; i++)
array[i] = 0;
}
Matrix::Matrix(int n, int* a)
{
num = n;
for (int i = 0; i < num; i++)
array[i] = a[i];
}
Matrix::Matrix(Matrix& c)
{
num = c.num;
for (int i = 0; i < c.num; i++)
array[i] = c.array[i];
}
Matrix Matrix::operator+(const Matrix& c)
{
Matrix x;
x.num = c.num;
for (int i = 0; i < num; i++)
x.array[i] = array[i] + c.array[i];
return x;
}
Matrix Matrix::operator-(const Matrix& c)
{
Matrix x;
x.num = c.num;
for (int i = 0; i < num; i++)
x.array[i] = array[i] - c.array[i];
return x;
}
void Matrix::show()
{
int i, k = 0;
for (i = 0; i < num; i++) {
cout << array[k++]<<" ";
}
cout << endl;
}
int main()
{
//freopen("1.txt", "r", stdin);
int  t, i, j, n, a[200], b[200];
while (cin >> t) {
while (cin >> n) {
for (i = 0; i < n; i++)
cin >> a[i];
for (j = 0; j < n; j++)
cin >> b[j];
Matrix x(n, a), y(n, b), z, w;
z = x + y;
z.show();
w = x - y;
w.show();
}
}
return 0;
}

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