c++的类模块，具体化和继承关系

本文主要是介绍c++的类模块，具体化和继承关系，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

1.类模版及它的全具体化，半具体化

template<typename Tl,typename T2)
class Test{
public:
T1 m_a;
T2 m_b;
Test(T1 a,T1 b):m_a(a),m_b(b){qDebug()<< "m_a"<<m_a;}

/类模板全具体化
template<>
class Test<int,string>
{
public:
int m_a;
string m_b;
Test(int a, string b):m_a(a),m_b(b)
{qDebug()<< "m_a"<<m_a;
}

//类模板半具体化
template<typename T>
class Test<T,string>
{
public:
T m_a;
string m_b;
Test(T a, string b):m_a(a),m_b(b)
{
qDebug()<<"m_a"<<m_a;
}
}

2.模板之间的继承（3种）关系 。（照顾好基类的构造函数）

2.1模版类继承普通类

//普通类
class AA
{
public:
int m_a;
string m b;
AA(int a,string b):m_a(a),m_b(b)
{
qDebug()<<"m_a"<<this->m_a;
}	
}

//类模板继承普通类
template<typename T1,typename T2>
class Test:public AA
{
public:
T1 m_a;
T1 m_b;
Test(Tl a,Tl b,int c,string d):m_a(a),m_b(b),AA(c,d)
{
qDebug()<< "m_a"<<m_a;
}

怎么使用

int main(int argc, char *argv[])
Test<int,double> ts(7,9,3,"birdsB");

2.2普通类继承模版类

//先写模版类
template<typenameTl,typenameT2>class BB{
public:
})
Tl m_a;T2 m b;
BB(T1 a,T2 b):m_a(a),m_b(b){qDebug()<<"m_a"<<this->m_a;}//写普通类继承模版类
template<typename Tl,typename T2>class AA:public BB<T1.T2>{
public:
int m a;
string m b;
AA(int a,string b,Tl c,T2 d):m_a(a),m_b(b),BB<T1,T2>(c,d)
{
qDebug()<<"m_a"<<this->m_a;
}

使用方法

int main(int argc, char *argv[])
{
AA<int,string> a(4,"he",5,"dgf");
}

2.3类模板继承类模板

//模版类：BB
template<typenameTl,typenameT2>class BB
{
public:
Tl m_a;
T2 m b;
BB(T1 a,T2 b):m_a(a),m_b(b)
{
qDebug()<<"m_a"<<this->m_a
}
}

模版类CC继承BB
template<typename Tl,typename T2,typename T3,typename T4)
class cc:public BB<T3,T4>
{
public:
T1 m_a;
T2 m_b;
CC(T1 a,T2 b,T3 c,T4 d):m_a(a),m_b(b),BB<T3,T4>(c,d)
{
qDebug()<<"m_a"<<this->m_a;
}void show();

怎么使用

int main(int argc, char *argv[])
{
CC<int,string,double,string> a(4,"he",5.0,"dgf");
}

模版类继承模版类，成员变量类外实现

template<typename Tl,typename T2,typename T3,typename T4)void BB<T1,T2,T3,T4>::show()
{}

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