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题目:
Your task is to calculate the sum of some integers.
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
Sample Input
3 4 1 2 3 4 5 1 2 3 4 5 3 1 2 3
Sample Output
10156
题意:
给你一个n,代表有n组测试数据,然后后面的n行,每一行的第一个数字m代表要求后面的m个数字的和;
格式需要注意,每两个结果之间有一个空行。
代码如下:
JAVA:
import java.util.Scanner;public class Main {
public static void main(String[] args) {Scanner input=new Scanner(System.in);int n,m,a,s;n=input.nextInt();while(n-->0) {m=input.nextInt();s=0;for(int i=0;i<m;i++) {a=input.nextInt();s=s+a;}System.out.println(s);if(n!=0)System.out.println();}
}
}
C++:
#include<stdio.h>
int main()
{int N;scanf("%d",&N);while(N--){int i,M,n,sum=0;scanf("%d",&M);for(i=0;i<M;i++){scanf("%d",&n);sum=sum+n;}printf("%d\n",sum);if(N!=0)printf("\n");}return 0;
}
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