本文主要是介绍PAT 1028 List Sorting [排序],希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
Excel can sort records according to any column. Now you are supposed to imitate this function.
Input Specification:
Each input file contains one test case. For each case, the first line contains two integers N (≤105) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).
Output Specification:
For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.
Sample Input 1:
3 1
000007 James 85
000010 Amy 90
000001 Zoe 60
Sample Output 1:
000001 Zoe 60
000007 James 85
000010 Amy 90
Sample Input 2:
4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98
Sample Output 2:
000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60
Sample Input 3:
4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90
Sample Output 3:
000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90
-------------------------------我是题目和代码的分割线-------------------------------
#include<cstdio>
#include<algorithm>
#include<string.h>using namespace std;struct student
{char id[7],sname[8];int grade;
}stu[100005];bool cmp1(student a,student b)
{return strcmp(a.id,b.id)<0;
}//注意一下字符类型不能直接比大小 用strcmp
bool cmp2(student a,student b)
{if(strcmp(a.sname,b.sname)!=0) return strcmp(a.sname,b.sname)<0;return strcmp(a.id,b.id)<0;
}bool cmp3(student a,student b)
{if(a.grade!=b.grade) return a.grade<b.grade;return strcmp(a.id,b.id)<0;
}int main()
{int n,c,i;scanf("%d%d",&n,&c);for(i=0;i<n;i++)scanf("%s%s%d",stu[i].id,stu[i].sname,&stu[i].grade);if(c==1) sort(stu,stu+n,cmp1);if(c==2) sort(stu,stu+n,cmp2);if(c==3) sort(stu,stu+n,cmp3);for(i=0;i<n;i++)printf("%s %s %d\n",stu[i].id,stu[i].sname,stu[i].grade);
}
这篇关于PAT 1028 List Sorting [排序]的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!