Vim--编程珠玑向量翻转

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#include<iostream>
#include<vector>using namespace std;void FindNumberOfMoreTwoTimesAppear(int pInt[], int length)
{// pInt 所指数组为有序数组, // length 数组长度if(pInt == NULL || length <= 0) return;for(int i = 0; i < length; i++){if((pInt[i] == pInt[i+1]) && (i < length -1)){std::cout << "i = " << i << ", " << pInt[i] << std::endl;}} }void RotateVectorValue(vector<char>& Src)
{if(Src.size() <= 1) return ;vector<char>::iterator pBegin = Src.begin();vector<char>::iterator pEnd = Src.end() - 1; int len = Src.size();if(len & 0x01){while(pBegin != pEnd){swap(*pBegin++, *pEnd--);            }}else{while(pEnd > pBegin){swap(*pBegin++, *pEnd--);}  }
}void PrintVector(vector<char>& Input)
{if(!Input.size()){return;}vector<char>::iterator Begin = Input.begin();vector<char>::iterator End   = Input.end();vector<char>::iterator it = Begin;for(it = Begin; it != End; it++){std::cout << *it << '\t';}std::cout << std::endl;
}int main()
{std::cout << "sizeof(int) = " << sizeof(int) << std::endl;std::cout << "sizeof(char) = " << sizeof(char) << std::endl;std::cout << "sizeof(double) = " << sizeof(double) << std::endl;int a[10] = {1,2,3,3,4,5,6,6,8,9};FindNumberOfMoreTwoTimesAppear(a, 10);vector<char> Src1, Src2;Src1.push_back('a');Src1.push_back('b');Src1.push_back('c');std::cout << "Raw data of Src1: " << '\n';PrintVector(Src1);RotateVectorValue(Src1);std::cout << "After rotate of Src1: " << '\n';PrintVector(Src1);std::cout << std::endl;Src2 = Src1;Src2.push_back('d');std::cout << "Raw data of Src2: " << '\n';PrintVector(Src2);RotateVectorValue(Src2);std::cout << "After rotate of Src2: " << '\n';PrintVector(Src2);return 0;
}