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show databases ;
use schoolSql;create table if not exists student(stu_id int(10),stu_name varchar(10),stu_age datetime,stu_gender varchar(10)
);insert into student values
('1','刘邦','1000-01-01','男'),
('2','吕雉','1000-01-02','女'),
('3','项羽','1000-01-03','男'),
('4','虞姬','1000-01-04','女');create table if not exists course(cou_id int(10),cou_name varchar(10),tea_id int(10)
);insert into course values
('1','语文','2'),
('2','数学','3'),
('3','英语','1');create table if not exists teacher(tea_id int(10) primary key ,tea_name varchar(20)
);
insert into teacher values('1','张三'),('2','李四'),('3','王五');select * from teacher;drop table result;
create table if not exists result(stu_id int(10),cou_id int(10),score decimal (18,1)
);insert into result values
('1','2',90),
('1','3',74),
('2','1',85),
('2','2',65),
('2','3',75),
('3','1',43),
('3','2',50),
('4','1',88),
('4','2',43),
('4','3',99);# 1、查询"1"课程比"2"课程成绩高的学生的信息及课程分数
select s.* ,b.score as '1分数',c.score as '2分数'
from student as s
inner join result b on b.stu_id=s.stu_id and b.cou_id='1'
inner join result c on c.stu_id=s.stu_id and c.cou_id='2'
where b.score>c.score;#2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
select s.*,r.score '1分数',c.score '2分数'
from student s
left join result r on s.stu_id = r.stu_id and r.cou_id='1'
left join result c on c.stu_id=s.stu_id and c.cou_id='2'
where r.score<c.score;#3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
select s.stu_id,s.stu_name ,avg(score) as avg_score
from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
HAVING avg_score>=60;#4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
select s.stu_id,s.stu_name,avg(score) as avg_score
from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
having avg_score<60;#5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
select s.stu_id,s.stu_name,count(r.cou_id) as count,sum(r.score) as sum_score
from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name;#6、查询"李"姓老师的数量
select count(t.tea_name)
from teacher as t where t.tea_name like '李%';#7、查询学过"张三"老师授课的同学的信息
select s.*
from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
left join teacher t on c.tea_id = t.tea_id
where t.tea_name='张三';#8、查询没学过"张三"老师授课的同学的信息
/* 错误
select s.*
from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
left join teacher t on c.tea_id = t.tea_id
where t.tea_name!='张三';*/select s2.* from student as s2
where s2.stu_id not in
(select s.stu_id
from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
left join teacher t on c.tea_id = t.tea_id
where t.tea_name='张三');#9、查询学过编号为"1"并且也学过编号为"2"的课程的同学的信息
select s.*
from student as s
left join result r on s.stu_id = r.stu_id
left join result r2 on s.stu_id=r2.stu_id
where r.cou_id='1' and r2.cou_id='2';#10、查询学过编号为"1"但是没有学过编号为"2"的课程的同学的信息
select s.* from student as s
left join result r on s.stu_id = r.stu_id
left join result r2 on s.stu_id=r2.stu_id
where r.cou_id='1' and r2.cou_id is null ;#11、查询没有学全所有课程的同学的信息#方法1
select s.* from student as s
left join result r1 on s.stu_id = r1.stu_id
and r1.cou_id='1'
left join result r2 on s.stu_id=r2.stu_id
and r2.cou_id='2'
left join result r3 on s.stu_id=r3.stu_id
and r3.cou_id='3'
where r1.score is null or r2.score is null or r3.score is null ;#方法2
SELECT st.stu_id,st.stu_name,st.stu_age,stu_gender
FROM student st
LEFT JOIN result sc ON st.stu_id=sc.stu_id
GROUP BY st.stu_id ,stu_name,stu_age,stu_gender
HAVING COUNT(sc.score)<3;#12、查询至少有一门课与学号为"1"的同学所学相同的同学的信息
select distinct s.* from student as s
left join result r on s.stu_id = r.stu_id
where r.cou_id in(select r2.cou_id from result r2left join student s2 on s2.stu_id = r2.stu_idwhere r2.stu_id='1');#13、查询和"01"号的同学学习的课程完全相同的其他同学的信息
#使用GROUP_CONCAT函数和GROUP BY
select s.* from student as s where stu_id in(select r.stu_id from(select * from result where stu_id='1') as rjoin result as r2 on r.cou_id=r2.cou_idgroup by r2.stu_idhaving count(*)=(select count(*) from result where r.stu_id='1' group by r.stu_id))
and stu_id<>'1';#14、查询没学过"张三"老师讲授的任一门课程的学生姓名
select s.stu_name from student as s
where s.stu_id not in(select s2.stu_id from student as s2left join result r on s2.stu_id = r.stu_idleft join course c on r.cou_id = c.cou_idleft join teacher t on c.tea_id = t.tea_idwhere t.tea_name='张三');#15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩
select s.stu_id, s.stu_name,avg(r.score) from student as s
left join result r on s.stu_id = r.stu_id
where r.stu_id in(select r.stu_id from result rwhere r.score<60 or r.score is nullgroup by r.stu_idhaving count(1)>=2)
group by s.stu_id, s.stu_name;#16、检索"01"课程分数小于60，按分数降序排列的学生信息
select s.* from student as s
left join result r on s.stu_id = r.stu_id
where r.stu_id in(select r.stu_id from resultwhere r.cou_id='1' and r.score<60)
order by r.score desc ;#17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
select s.stu_id,s.stu_name,(case when avg(r4.score) is null then 0 else avg(r4.score) end) "平均分",(case when r1.score is null then 0 else r1.score end) "语文",(case when r2.score is null then 0 else r2.score end) "数学",(case when r3.score is null then 0 else r3.score end) "英语"
from student as s
left join result r1 on s.stu_id = r1.stu_id and r1.cou_id='1'
left join result r2 on s.stu_id=r2.stu_id and r2.cou_id='2'
left join result r3 on s.stu_id=r3.stu_id and r3.cou_id='3'
left join result r4 on s.stu_id=r4.stu_id
group by s.stu_id, s.stu_name, (case when r1.score is null then 0 else r1.score end), (case when r2.score is null then 0 else r2.score end), (case when r3.score is null then 0 else r3.score end)
order by avg(r4.score) desc ;#18、查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率
# 及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90
select c.cou_id,c.cou_name,max(r.score) "最高分" ,min(r.score) "最高分",avg(r.score) "平均分",sum(case when r.score>=60 then 1 else 0 end)/count(1) "及格率",sum(case when r.score>=70 and r.score<80 then 1 else 0 end)/count(1) "中等率",sum(case when r.score>=80 and r.score<90 then 1 else 0 end)/count(1) "优良率",sum(case when r.score>=90 then 1 else 0 end)/count(1) "优秀率"
from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_id, c.cou_name;#19、按各科成绩进行排序，并显示排名
select c.cou_name ,r.score from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_name, r.score
order by c.cou_name, r.score desc;#20、查询学生的总成绩并进行排名
select s.stu_id,s.stu_name,sum(r.score) as "总成绩" from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
order by sum(r.score) desc;#21、查询不同老师所教不同课程平均分从高到低显示
select t.tea_id,t.tea_name,c.cou_id,avg(r.score) from teacher as t
left join course c on t.tea_id = c.tea_id
left join result r on c.cou_id = r.cou_id
group by t.tea_id, t.tea_name,c.cou_id
order by avg(r.score) desc;#22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
select t1.* from
(select s.*,c.cou_id,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
inner join course c on r.cou_id = c.cou_id and c.cou_id='1'
order by r.score desc limit 1,2)t1union allselect t2.* from
(select s.*,c.cou_id,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
inner join course c on r.cou_id = c.cou_id and c.cou_id='2'
order by r.score desc limit 1,2)t2union allselect t3.* from
(select s.*,c.cou_id,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
inner join course c on r.cou_id = c.cou_id and c.cou_id='3'
order by r.score desc limit 1,2) t3;#23、统计各科成绩各分数段人数：课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比
select c.cou_id,c.cou_name,sum(case when r.score >=0 and r.score<60 then 1 else 0 end) as "0-60",sum(case when r.score>=60 and r.score<70 then 1 else 0 end) as "70-60",sum(case when r.score>=70 and r.score<85 then 1 else 0 end) as "85-70",sum(case when r.score>=85 and r.score<100 then 1 else 0 end) as"100-85",sum(case when r.score >=0 and r.score<60 then 1 else 0 end)/count(1) as "0-60百分比",sum(case when r.score>=60 and r.score<70 then 1 else 0 end)/count(1) as "70-60百分比",sum(case when r.score>=70 and r.score<85 then 1 else 0 end)/count(1) as "85-70百分比",sum(case when r.score>=85 and r.score<100 then 1 else 0 end)/count(1) as"100-85百分比"
from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_id, c.cou_name;#24、查询学生平均成绩及其名次
#自己对自己左交，查看比自己分数高的有几个
select s.stu_name,avg(r.score) from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_name
order by avg(r.score) desc ;#25、查询各科成绩前三名的记录
SELECT a.*,COUNT(b.cou_id)+1 AS ascore
FROM result a
LEFT JOIN result b
ON a.cou_id=b.cou_id AND a.score<b.score
GROUP BY 1,2,3
HAVING ascore<=3
ORDER BY a.cou_id,ascore;
#方法二
select s.stu_name,c.cou_name,count(r2.cou_id)+1 as ascore from result r
left join result r2 on r.cou_id=r2.cou_id and r.score<r2.score
left join student s on r.stu_id = s.stu_id
left join course c on r.cou_id = c.cou_id
group by s.stu_name, c.cou_name
having ascore<=3
order by c.cou_name,ascore;#26、查询每门课程被选修的学生数
select c.cou_name,count(r.cou_id) as "选修人数" from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_name;#27、查询出只有两门课程的全部学生的学号和姓名
select s.stu_id,s.stu_name from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
having count(r.cou_id)=2;#28、查询男生、女生人数
select s.stu_gender,count(1) from student as s
group by s.stu_gender;#29、查询名字中含有"羽"字的学生信息
select s.* from student as s
where s.stu_name like '%羽%';#30、查询同名同姓学生名单，并统计同名人数
select s.stu_name,count(1) from student as s
group by s.stu_name
having count(1)>1;#31、查询1000年出生的学生名单(注：Student表中Sage列的类型是datetime)
select s.* from student as s
where year(s.stu_age)=1000;#32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号
select r.cou_id,c.cou_name,avg(r.score) as avg_score from result as r
left join course c on r.cou_id = c.cou_id
group by r.cou_id, c.cou_name
order by avg_score desc ,r.cou_id ;#33、查询平均成绩大于等于80的所有学生的学号、姓名和平均成绩
select s.stu_id,s.stu_name,avg(r.score) "平均分" from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
having avg(r.score)>=80;#34、查询课程名称为"数学"，且分数低于60的学生姓名和分数
select s.stu_id,s.stu_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
inner join course c on r.cou_id = c.cou_id
where c.cou_name='数学'
having r.score<60;#35、查询所有学生的课程及分数情况
select s.stu_id,s.stu_name,c.cou_id,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
group by s.stu_id, s.stu_name, c.cou_id, c.cou_name, r.score;#36、查询任何一门课程成绩在80分以上的姓名、课程名称和分数
select s.stu_name,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
group by s.stu_name, c.cou_name, r.score
having r.score>80;#37、查询不及格的课程
select s.stu_id,s.stu_name,c.cou_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
where r.score<60
group by s.stu_id, s.stu_name, c.cou_name, r.score;#38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名
select s.stu_id,s.stu_name,r.score from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
where c.cou_id='1' and r.score>80;#39、求每门课程的学生人数
select c.cou_name,count(c.cou_id) from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_name;#40、查询选修"张三"老师所授课程的学生中，成绩最高的学生信息及其成绩
select s.*,r.score from student as s
left join result r on s.stu_id = r.stu_id
left join course c on r.cou_id = c.cou_id
left join teacher t on c.tea_id = t.tea_id
where t.tea_name='张三'
order by r.score desc limit 1;#41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
select r.stu_id,r.cou_id,r.score from result as r
left join result r2 on r.score=r2.score and r.cou_id <>r2.cou_id
#group by 1,2,3
group by r.stu_id, r.cou_id, r.score
having count(r2.stu_id)>0;#方法2
select r.* from result as r
left join result r2 on r.score=r2.score and r.cou_id <>r2.cou_id
group by 1,2,3
having count(r2.stu_id)>0;#42、查询每门功成绩最好的前两名
select r1.stu_id,r1.cou_id,r1.score from result as r1
left join result r2 on r1.cou_id=r2.cou_id and r1.score<r2.score
group by r1.stu_id, r1.cou_id, r1.score
having count(r2.cou_id)<2
order by r1.cou_id,r1.score desc;#43、统计每门课程的学生选修人数（超过2人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列
select c.cou_id,count(r.cou_id) as acount from course as c
left join result r on c.cou_id = r.cou_id
group by c.cou_id
having acount>2
order by acount desc ,c.cou_id;#44、检索至少选修两门课程的学生学号
select s.stu_id,s.stu_name ,count(r.cou_id) as acount from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name
having acount>=2;#45、查询选修了全部课程的学生信息
select s.stu_id,s.stu_name,s.stu_age,s.stu_gender from student as s
left join result r on s.stu_id = r.stu_id
group by s.stu_id, s.stu_name, s.stu_age, s.stu_gender
having count(r.cou_id)=3;#46、查询各学生的年龄
select s.*,(YEAR(CURDATE())-YEAR(s.stu_age))as "年龄" from student as s;#47、查询本周过生日的学生
select s.* from student as s
where weekofyear(s.stu_age)=weekofyear(curdate());#48、查询下周过生日的学生
select s.* from student as s
where weekofyear(s.stu_age)=weekofyear(curdate())+1;#49、查询本月过生日的学生
select s.* from student as s
where month(s.stu_age)=month(curdate());#50、查询上月过生日的学生
select s.* from student as s
where month(s.stu_age)=month(curdate())-1;
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