【定义一个结构体变量（包括年、月、日）。计算该日在本年中是第几天，注意闰年问题。】

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定义一个结构体变量（包括年、月、日）。计算该日在本年中是第几天，注意闰年问题。

我们首先判断该年是不是闰年，代码简单明了，就是有点费手。

#include<stdio.h>
struct data{
   int year;
   int month;
   int day;
};
int main(){
   struct data a[1];
   int year;
   int month;
   int day;
   scanf("%d %d %d",&a[0].year,&a[0].month,&a[0].day);
   if (a[0].year%4==0&&a[0].year%100!=0||a[0].year%400==0)
       switch(a[0].month){
       case 1:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,a[0].day,a[0].year);break;
       case 2:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,a[0].day+31,a[0].year);break;
       case 3:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+29+a[0].day,a[0].year);break;
       case 4:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+31+29+a[0].day,a[0].year);break;
       case 5:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+31+29+a[0].day,a[0].year);break;
       case 6:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+31+29+a[0].day,a[0].year);break;
       case 7:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+30+31+31+29+a[0].day,a[0].year);break;
       case 8:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+30+31+31+29+a[0].day,a[0].year);break;
       case 9:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+31+30+31+30+31+31+29+a[0].day,a[0].year);break;
case 10:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+31+30+31+30+31+31+29+a[0].day,a[0].year);break;
case 11:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+31+30+31+30+31+31+29+a[0].day,a[0].year);break;
   case 12:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+30+31+31+30+31+30+31+31+29+a[0].day,a[0].year);break;
   }
else
   switch(a[0].month){
       case 1:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,a[0].day,a[0].year);break;
       case 2:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,a[0].day+31,a[0].year);break;
       case 3:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+28+a[0].day,a[0].year);break;
       case 4:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+31+28+a[0].day,a[0].year);break;
       case 5:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+31+28+a[0].day,a[0].year);break;
       case 6:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+31+28+a[0].day,a[0].year);break;
       case 7:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+30+31+31+28+a[0].day,a[0].year);break;
       case 8:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+30+31+31+28+a[0].day,a[0].year);break;
       case 9:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+31+30+31+30+31+31+28+a[0].day,a[0].year);break;
case 10:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+31+30+31+30+31+31+28+a[0].day,a[0].year);break;
case 11:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,31+30+31+31+30+31+30+31+31+28+a[0].day,a[0].year);break;
   case 12:printf("%d/%d is the %dth day in %d.",a[0].month,a[0].day,30+31+30+31+31+30+31+30+31+31+28+a[0].day,a[0].year);break;
return 0;
}