持久性内存编程——内存分配使用举例

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前面有了两篇讲解内存分配的博文：

持久性内存编程——事务性动态内存分配：https://blog.csdn.net/SweeNeil/article/details/90547136

持久性内存编程——原子分配动态内存：https://blog.csdn.net/SweeNeil/article/details/90444432

其实写得都有点简单，没有一个比较简单具体的案例，下面就把具体的内存分配的简单案例整理出来。

目录

一、事务性动态内存分配

二、原子性动态内存分配

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一、事务性动态内存分配

rect_calc.c:

#include <stdio.h>
#include <string.h>
#include <libpmemobj.h>POBJ_LAYOUT_BEGIN(rect_calc);
POBJ_LAYOUT_ROOT(rect_calc, struct my_root);
POBJ_LAYOUT_TOID(rect_calc, struct rectangle);
POBJ_LAYOUT_END(rect_calc);struct rectangle {int a;int b;
};struct my_root {TOID(struct rectangle) rect;
};int area_calc(const TOID(struct rectangle) rect) {return D_RO(rect)->a * D_RO(rect)->b;
}int main(int argc, char *argv[])
{if (argc != 2) {printf("usage: %s file-name\n", argv[0]);return 1;}PMEMobjpool *pop = pmemobj_create(argv[1],POBJ_LAYOUT_NAME(rect_calc), PMEMOBJ_MIN_POOL, 0666);if (pop == NULL) {perror("pmemobj_create");return 1;}TOID(struct my_root) root = POBJ_ROOT(pop, struct my_root);TX_BEGIN(pop) {TX_ADD(root); /* we are going to operate on the root object */TOID(struct rectangle) rect = TX_NEW(struct rectangle);D_RW(rect)->a = 5;D_RW(rect)->b = 10;D_RW(root)->rect = rect;} TX_ENDint p = area_calc(D_RO(root)->rect);const TOID(struct rectangle) rects = D_RO(root)->rect;printf("%d\n", p);TX_BEGIN(pop) {TX_ADD(root);TX_FREE(D_RW(root)->rect);D_RW(root)->rect = TOID_NULL(struct rectangle);} TX_END}

编译：

gcc rect_calc.c -o rect_calc -lpmemobj -lpmem -pthread

运行：

sudo ./rect_calc /mnt/pmemdir/rect_calc
50

感觉现在对于这个持久性内存编程还不够熟悉，编写起来不够灵活，对于layout的声明需要放在前面，不然编译可能会报错，当我把layout的声明放在了结构体之后，报出了如下问题：

测试在后面打印出 a与b的值使用了下面两种方式，都编译报错。

两种方式：

报错：

二、原子性动态内存分配

alloc.c：

#include <stdio.h>
#include <string.h>
#include <libpmemobj.h>POBJ_LAYOUT_BEGIN(rect_calc);
POBJ_LAYOUT_ROOT(rect_calc, struct my_root);
POBJ_LAYOUT_TOID(rect_calc, struct rectangle);
POBJ_LAYOUT_END(rect_calc);struct rectangle {int a;int b;
};struct my_root {TOID(struct rectangle) rect;
};int rect_construct(PMEMobjpool *pop, void *ptr, void *arg) {struct rectangle *rect = ptr;rect->a = 5;rect->b = 10;pmemobj_persist(pop, rect, sizeof *rect);return 0;
}int perimeter_calc(const TOID(struct rectangle) rect) {return D_RO(rect)->a * D_RO(rect)->b;
}int main(int argc, char *argv[])
{if (argc != 2) {printf("usage: %s file-name\n", argv[0]);return 1;}PMEMobjpool *pop = pmemobj_create(argv[1],POBJ_LAYOUT_NAME(rect_calc), PMEMOBJ_MIN_POOL, 0666);if (pop == NULL) {perror("pmemobj_create");return 1;}TOID(struct my_root) root = POBJ_ROOT(pop, struct my_root);POBJ_NEW(pop, &D_RW(root)->rect, struct rectangle, rect_construct, NULL);int p = perimeter_calc(D_RO(root)->rect);/* busy work */printf("%d\n", p);POBJ_FREE(&D_RW(root)->rect);
}

编译：

gcc alloc.c -o alloc -lpmemobj -lpmem -pthread

运行：

其实这两种方式的编程还是挺简单的，但是要用熟还是需要花点功夫。

 

参考：

http://pmem.io/2015/06/18/ntx-alloc.html

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