Python暴力破解凯撒密码（界面化实现）

和我的上一篇文章中的代码逻辑相同，无非就是将key从0-25遍历一遍，直接放代码

from tkinter import *
def hydry(event):message=str(b1.get()).upper()letter='ABCDEFGHIJKLMNOPQRSTUVWXYZ'sult = ''for key in range(26):for i in message:if i in letter:num = letter.find(i)num = num - keyif num >= len(letter):num = num - len(letter)if num < 0:num = num + len(letter)sult = sult + letter[num]else:sult = sult + isult=sult+'\n'lib.config(text=str(sult))
root=Tk()
root.title('暴力破解凯撒密码')
root.geometry('1080x720')b1=Entry(root,text='输入待破解的密文')
b1.place(relx=0.1,rely=0.1,relwidth=0.5,relheight=0.1)
b2=Button(root,text='开始破解')
b2.place(relx=0.1,rely=0.2,relwidth=0.1,relheight=0.1)
b2.bind('<1>',hydry)
lib=Label(root,text='结果')
lib.place(relx=0.1,rely=0.3, relwidth=0.6, relheight=0.7)
root.mainloop()

运行结果：