共模攻击

本文主要是介绍共模攻击，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

给了两个密文和两个密钥

提取公钥信息

from Crypto.PublicKey import RSA
import libnum
import gmpy2c1=libnum.s2n(open('cipher1.txt','rb').read())
c2=libnum.s2n(open('cipher2.txt','rb').read())pub1=RSA.importKey(open('publickey1.pem').read())
pub2=RSA.importKey(open('publickey2.pem').read())n1 = pub1.n
e1 = pub1.e
n2 = pub2.n
e2 = pub2.eprint(n1)
print(n2)
print(e1)
print(e2)

n1 = 13060424286033164731705267935214411273739909173486948413518022752305313862238166593214772698793487761875251030423516993519714215306808677724104692474199215119387725741906071553437840256786220484582884693286140537492541093086953005486704542435188521724013251087887351409946184501295224744819621937322469140771245380081663560150133162692174498642474588168444167533621259824640599530052827878558481036155222733986179487577693360697390152370901746112653758338456083440878726007229307830037808681050302990411238666727608253452573696904083133866093791985565118032742893247076947480766837941319251901579605233916076425572961
n2 = 13060424286033164731705267935214411273739909173486948413518022752305313862238166593214772698793487761875251030423516993519714215306808677724104692474199215119387725741906071553437840256786220484582884693286140537492541093086953005486704542435188521724013251087887351409946184501295224744819621937322469140771245380081663560150133162692174498642474588168444167533621259824640599530052827878558481036155222733986179487577693360697390152370901746112653758338456083440878726007229307830037808681050302990411238666727608253452573696904083133866093791985565118032742893247076947480766837941319251901579605233916076425572961
e1 = 117
e2 = 65537

from Crypto.PublicKey import RSA
import libnum
import gmpy2c1=libnum.s2n(open('cipher1.txt','rb').read())
c2=libnum.s2n(open('cipher2.txt','rb').read())pub1=RSA.importKey(open('publickey1.pem').read())
pub2=RSA.importKey(open('publickey2.pem').read())
n = pub1.n
e1= pub1.e
e2= pub2.es = gmpy2.gcdext(e1,e2)
s1 = s[1]
s2 = s[2]if s1<0:s1 = -s1c1 = gmpy2.invert(c1, n)
elif s2<0:s2 = -s2c2 = gmpy2.invert(c2, n)m = pow(c1,s1,n)*pow(c2,s2,n) % n
flag = libnum.n2s(m)
print(flag)

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