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题目
nc文件中lon的范围是0-360
我只会两种方法
方法1：
{lon|(/350,352.5,355,357.5,0,2.5,5,7.5,10,12.5,15,17.5,20/)}
begin
f = addfile("D:/cygwin/home/wunan/hgt.day.mean.200001-200004.nc","r")hgt = f->hgt
hgtF = short2flt(f->hgt)
time = f->timetime_1 = cd_calendar(time,2)
timeInd1 = ind(time_1.eq.20000101)
timeInd2 = ind(time_1.eq.20000107)
hgtF_sub = hgtF(time|timeInd1:timeInd2,{level|(/250,500,850/)},{lat|0:90},{lon|(/350,352.5,355,357.5,0,2.5,5,7.5,10,12.5,15,17.5,20/)})printVarSummary(hgtF_sub)end方法2：直接350：20！！！！
begin
f = addfile("D:/cygwin/home/wunan/hgt.day.mean.200001-200004.nc","r")hgt = f->hgt
hgtF = short2flt(f->hgt)
time = f->timetime_1 = cd_calendar(time,2)
timeInd1 = ind(time_1.eq.20000101)
timeInd2 = ind(time_1.eq.20000107)
hgtF_sub = hgtF(time|timeInd1:timeInd2,{level|(/250,500,850/)},{lat|0:90},{lon|350:20})printVarSummary(hgtF_sub)end结果
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