CF B. Sonya and Exhibition

2023-10-25 04:38
文章标签 cf exhibition sonya

本文主要是介绍CF B. Sonya and Exhibition,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!

A. Sonya and Hotels
题目网址 点击打开链接
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

Sonya decided that having her own hotel business is the best way of earning money because she can profit and rest wherever she wants.

The country where Sonya lives is an endless line. There is a city in each integer coordinate on this line. She has nn hotels, where the ii-th hotel is located in the city with coordinate xixi. Sonya is a smart girl, so she does not open two or more hotels in the same city.

Sonya understands that her business needs to be expanded by opening new hotels, so she decides to build one more. She wants to make the minimum distance from this hotel to all others to be equal to dd. The girl understands that there are many possible locations to construct such a hotel. Thus she wants to know the number of possible coordinates of the cities where she can build a new hotel.

Because Sonya is lounging in a jacuzzi in one of her hotels, she is asking you to find the number of cities where she can build a new hotel so that the minimum distance from the original nn hotels to the new one is equal to dd.

Input

The first line contains two integers nn and dd (1n1001≤n≤1001d1091≤d≤109) — the number of Sonya's hotels and the needed minimum distance from a new hotel to all others.

The second line contains nn different integers in strictly increasing order x1,x2,,xnx1,x2,…,xn (109xi109−109≤xi≤109) — coordinates of Sonya's hotels.

Output

Print the number of cities where Sonya can build a new hotel so that the minimum distance from this hotel to all others is equal to dd.

Examples
input
Copy
4 3
-3 2 9 16
output
Copy
6
input
Copy
5 2
4 8 11 18 19
output
Copy
5
Note

In the first example, there are 66 possible cities where Sonya can build a hotel. These cities have coordinates 6−6556612121313, and 1919.

In the second example, there are 55 possible cities where Sonya can build a hotel. These cities have coordinates 226613131616, and 2121


有一个长为n的地方可以放rose和lily两种花,有d位游客,每位游览不同的区间,现要求每位游客游览的区间内rose数乘Lily数最大,想了好久,以为是爆搜或者是动态规划一类的难题,果断放弃。

晚上搜题解,才发现是一道考验智商的大水题,只需保证0101010这样的顺序就可以保证每位游客经历的区间不同花的个数最多了。深感遗憾和震惊!!!!

#include<bits/stdc++.h>
using namespace std;int main()
{int a,b,t;scanf("%d%d",&a,&b);for(int i=0;i<b;i++){cin>>t;cin>>t;}for(int i=0;i<a;i++){if(i&1)cout<<'1';elsecout<<'0';}cout<<endl;return 0;
}

这篇关于CF B. Sonya and Exhibition的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!



http://www.chinasem.cn/article/280067

相关文章

cf 164 C 费用流

给你n个任务,k个机器,n个任务的起始时间,持续时间,完成任务的获利 每个机器可以完成任何一项任务,但是同一时刻只能完成一项任务,一旦某台机器在完成某项任务时,直到任务结束,这台机器都不能去做其他任务 最后问你当获利最大时,应该安排那些机器工作,即输出方案 具体建图方法: 新建源汇S T‘ 对任务按照起始时间s按升序排序 拆点: u 向 u'连一条边 容量为 1 费用为 -c,

CF 508C

点击打开链接 import java.util.Arrays;import java.util.Scanner;public class Main {public static void main(String [] args){new Solve().run() ;} }class Solve{int bit[] = new int[608] ;int l

【CF】C. Glass Carving(二分 + 树状数组 + 优先队列 + 数组计数)

这题简直蛋疼死。。。。。 A了一下午 #include<cstdio>#include<queue>#include<cstring>#include<algorithm>using namespace std;typedef long long LL;const int maxn = 200005;int h,w,n;int C1[maxn],C2[maxn];int

【CF】E. Anya and Cubes(双向DFS)

根据题意的话每次递归分3种情况 一共最多25个数,时间复杂度为3^25,太大了 我们可以分2次求解第一次求一半的结果,也就是25/2 = 12,记录结果 之后利用剩余的一半求结果 s-结果 = 之前记录过的结果 就可以 时间复杂度降低为 3 ^ (n/2+1) 题目链接:http://codeforces.com/contest/525/problem/E #include<set

【CF】D. Arthur and Walls(BFS + 贪心)

D题 解题思路就是每次检查2X2的方格里是否只有一个‘*’,如果有的话这个*就需要变成‘.’,利用BFS进行遍历,入队的要求是这个点为. 一开始将所有的'.'全部加入队列,如果碰到一个'*'变成'.'就入队,判断的时候从4个方向就行判断 题目链接:http://codeforces.com/contest/525/problem/D #include<cstdio>#include<

CF#271 (Div. 2) D.(dp)

D. Flowers time limit per test 1.5 seconds memory limit per test 256 megabytes input standard input output standard output 题目链接: http://codeforces.com/contest/474/problem/D We s

CF Bayan 2015 Contest Warm Up B.(dfs+暴力)

B. Strongly Connected City time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output 题目链接: http://codeforces.com/contest/475/probl

CF Bayan 2015 Contest Warm Up A.(模拟+预处理)

A. Bayan Bus time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output 题目链接: http://codeforces.com/contest/475/problem/A The fi

CF #278 (Div. 2) B.(暴力枚举+推导公式+数学构造)

B. Candy Boxes time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output 题目链接: http://codeforces.com/contest/488/problem/B There

CF#278 (Div. 2) A.(暴力枚举)

A. Giga Tower time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output 题目链接: http://codeforces.com/contest/488/problem/A Giga To