仔细观察就会发现K = pow(2, m) + pow(2, m-1) 数要翻转一次
/************************************************
* Author :Powatr
* Created Time :2015/10/20 18:06:07
* File Name :A.cpp************************************************/#include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std;#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 1e5 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;long long Pow(int n)
{long long res = 1;for(int i = 1; i <= n; i++)res *= 2;return res;
}int solve(long long k)
{int cout1 = 0;while(1){int m = log(k) / log(2);if(Pow(m) + Pow(m-1) == k){cout1++;k -= Pow(m);}else k -= Pow(m);if(k == 1||k == 0) break;}if(cout1 % 2 == 1) return 1;return 0;
}int main(){int T;long long k;scanf("%d", &T);for(int cas = 1; cas <= T; cas++){scanf("%lld", &k);printf("Case #%d: ", cas);int ans = solve(k);printf("%d\n", ans);}return 0;
}