1058 A+B in Hogwarts (20 分) 进制转换

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If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10^7], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

题意：输入两个数，求他们的和，有进制分别为17和29
思路：全部数字都要用long long类型，不然测试点会有过不去

#include<iostream>
#include<cstdio>
#include<stack> 
#include<queue>
#include<vector>
#include<algorithm>
#include<cstring>
#include<string>
#include<cmath>
#include<set>
#include<map>using namespace std;int main() {long long a,b,c,d,e,f;scanf("%lld.%lld.%lld %lld.%lld.%lld",&a,&b,&c,&d,&e,&f);long long num = a * 29 * 17 + b * 29 + c + d * 29 * 17 + e * 29 + f;long long bai = num / (29 * 17);num = num % (29 * 17);printf("%lld.%lld.%lld",bai,num / 29,num % 29);return 0;
}